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kifflom [539]
3 years ago
15

_____ are keys to reactivity

Chemistry
1 answer:
Elina [12.6K]3 years ago
5 0
Number of electron determine reactivity
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In some regions of the world, forests are cut down and then burned to create room for farmland. How might this local environment
UkoKoshka [18]

The answer is D.

<u>Explanation</u>

Without trees, no carbon dioxide will be released into the air. It would not raise oxygen levels, and it wouldn’t effect rising sea levels.

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3 years ago
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How an object accelerates when it changes direction?​
Mrrafil [7]

Answer:

An object which experiences either a change in the magnitude or the direction of the velocity vector can be said to be accelerating. This explains why an object moving in a circle at constant speed can be said to accelerate - the direction of the velocity changes.

Explanation:

7 0
3 years ago
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8.84 g of a compound is analyzed and found to contain 3.53 g of C, 0.295 g of H, 4.08 g of N, and 0.935 g of O. Which of the fol
svetoff [14.1K]

Answer:

Option 1 is correct. C10H10N10O2

Explanation:

Step 1: Data given

Mass of a compound = 8.84 grams

Mass of C = 3.53 grams

Mass of H = 0.295 grams

Mass of N = 4.08 grams

Mass of O = 0.935 grams

Atomic mass C = 12.01 g/mol

Atomic mass H = 1.01 g/mol

Atomic mass N = 14.0 g/mol

Atomic mass O = 16.0 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles C = 3.53 grams / 12.01 g/mol

Moles C = 0.294 moles

Moles H = 0.295 grams / 1.01 g/mol

Moles H = 0.292 moles

Moles N = 4.08 grams / 14.0 g/mol

Moles N = 0.291 moles

Moles O = 0.935 grams / 16 g/mol

Moles O = 0.0584 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.294 / 0.0584 = 5

H: 0.292 / 0.0584 = 5

N: 0.291/0.0584 = 5

O: 0.0584/0.0584 = 1

The empirical formula is C5H5N5O

Option 1 has this empirical formula

C10H10N10O2

4 0
4 years ago
More efficient plumbing reduces water pollution by _______. a. using more water b. using less water c. using cleaner water d. us
Aliun [14]

Answer:

b. using less water

Explanation:

Pollution can be defined as the physical degradation or contamination of the environment through an emission of harmful, poisonous and toxic chemical substances.

In the United States of America, the agency which was established by US Congress and saddled with the responsibility of overseeing all aspects of pollution, environmental clean up, pesticide use, contamination, and hazardous waste spills is the Environmental Protection Agency (EPA). Also, EPA research solutions, policy development, and enforcement of regulations through the resource Conservation and Recovery Act.

In homes and offices, an effective and efficient design of pipes and other water-related facilities would go a long way to reduce water pollution because the water used are well managed and properly disposed into sinkholes.

Hence, more efficient plumbing reduces water pollution by using less water

6 0
3 years ago
8. The protein in a 1.2846-g sample of an oat cereal is determined by a Kjeldahl analysis. The sample is digested with H2SO4, th
docker41 [41]

Answer: The %w/w protein in the sample is 15.2 %

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}    

\text{Moles of} HCl={0.09552\times 50.00}{1000}=0.0047moles

\text{Moles of} NaOH={0.05992\times 37.84}{1000}=0.0023moles

HCl+NaOH\rightarrow NaCl+H_2O  

According to stoichiometry :

1 mole of NaOH require 1 mole of HCl

Thus 0.0023 moles of NaOH will require=\frac{1}{1}\times 0.0023=0.0023moles  of HCl

moles of HCl used = (0.0047-0.0023) = 0.0024

NH_3+HCl\rightarrow NH_4Cl

1 mole of HCl uses = 1 mole of ammonia

Thus 0.0024 moles uses = \frac{1}{1}\times 0.0024=0.0024moles of ammonia

Mass of ammonia= moles\times {\text {Molar mass}}=0.0024\times 17g/mol=0.0408g

17 g of ammonia contains = 14 g of Nitrogen

Thus 0.0408 g of ammonia contains = \frac{14}{17}\times 0.0408=0.034 g of Nitrogen

Now 17.45 g of Nitrogen is present in = 100 g of protein

Thus 0.034 g of Nitrogen is present in =\frac{100}{17.45}\times 0.034=0.195g of protein

Now % w/w of protein = \frac{0.195}{1.2846}\times 100=15.2\%

Thus %w/w protein in the sample is 15.2%

8 0
3 years ago
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