One electron has a mass of<br> 1 amu<br> 2 amu<br> 0 amu<br> 3 amu

A car travels 500km in 9 hours. How fast was it going

Firdavs [7]

Answer:

about 55 kilometers per hour

Explanation:

distance divided by time = 500/9

6 0

3 years ago

A solution of saline may contain 1.81 mol of sodium chloride (NaCl). How many sodium atoms are present in the solution?

joja [24]

Answer:

1.09 x 10²⁴ atoms Na

Explanation:

In one mole of NaCl, there is also one mole of Na. To convert between moles and atoms, you need to use Avogadro's number. When writing the conversion, the desired unit (atoms) should be placed in the numerator to allow for the cancellation of units (moles). The final answer should have 3 sig figs to match the given number (1.81 mole).

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

1.81 moles Na 6.022 x 10²³ atoms
--------------------- x -------------------------------- = 1.09 x 10²⁴ atoms Na
1 mole

5 0

1 year ago

If you take Organic Chemistry Laboratory (CHM2211L) you will learn the term reflux. A reaction is considered to be at reflux whe

shutvik [7]

Answer : The temperature of the chloroform will be, $101.67^oF$

Explanation :

First we have to calculate the mass of chloroform.

$\text{Mass of chloroform}=\text{Density of chloroform}\times \text{Volume of chloroform}=1.4832g/ml\times 74.81ml=110.958g$

conversion used : $(1cm^3=1ml)$

Now we have to calculate the temperature of the chloroform.

Formula used :

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = amount of heat or energy = 1.46 kJ = 1460 J (1 kJ = 1000 J)

$c$ = specific heat capacity = $0.96J/g.K$

m = mass of substance = 110.958 g

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $25^oC=273+25=298K$

Now put all the given values in the above formula, we get:

$1460J=110.958g\times 0.96J/g.K\times (T_{final}-298)K$

$T_{final}=311.706K$

Now we have to convert the temperature from Kelvin to Fahrenheit.

The conversion used for the temperature from Kelvin to Fahrenheit is:

$^oC=\frac{5}{9}\times (^oF-32)$

As we know that, $K=^oC+273$ or, $K-273=^oC$

$K-273=\frac{5}{9}\times (^oF-32)$

$K=\frac{5}{9}\times (^oF-32)+273$ ...........(1)

Now put the value of temperature of Kelvin in (1), we get:

$311.706K=\frac{5}{9}\times (^oF-32)+273$

$T_{final}=101.67^oF$

Therefore, the temperature of the chloroform will be, $101.67^oF$

5 0

3 years ago

C2H4(g) + H2(g) → C2H6(g) ΔH = –137.5 kJ; ΔS = –120.5 J/K Calculate ΔG at 25 °C and determine whether the reaction is spontaneou

Katen [24]

Answer:-ΔG=-101.5KJ

Explanation:We have to calculate ΔG for the reaction so using the formula given in the equation we can calculate the \Delta G for the reaction.

We need to convert the unit ofΔS in terms of KJ/Kelvin as its value is given in terms of J/Kelvin

Also we need to convert the temperature in Kelvin as it is given in degree celsius.

$\Delta H=-137.5\\ \Delta S=-120J/K\\ \Delta S=-0.120KJ/K\\ T=25^{.C}\\ T=273+25=298 K\\ \Delta G=?\\ \Delta G=\Delta H-T\Delta S\\\Delta G=-137.5KJ-(278\times -0.120)\\ \Delta G=-137.5+35.76\\\Delta G=-101.74\\\Delta G=Negative$

After calculating forΔG we found that the value ofΔG is negative and its value is -101.74KJ

For a reaction to be spontaneous the value of \Delta G \ must be negative .

As the ΔG for the given reaction is is negative so the reaction will be spontaneous in nature.

In this reaction since the entropy of reaction is positive and hence when we increase the temperature term then the overall term TΔS would become more positive and hence the value of ΔG would be less negative .

Hence the value of ΔG would become more positive with the increase in temperature.

So we found the value of ΔG to be -101.74KJ

4 0

3 years ago

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Clouds are named for 3 different attributes including shape, _____________ & precipitation. *

mart [117]

Answer:

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4 0

3 years ago

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One electron has a mass of 1 amu 2 amu 0 amu 3 amu