We know,
1000 cm³ = 1 L
1 cm³ = 1 / 1000 L
508 cm³ = (1 / 1000) * 508 L =
0.5080 L
So, 508 cm³ = 0.5080 LNow,
We know,
22.4 L = 1 mole
1 L = 1 / 22.4 mole
0.5080 L = (1 / 22.4) * 0.5080L =
0.0227 moles
So, 0.0277 moles moles of are added to the tank before it is used for paintball.
<span>let's start:
16 g NaOH has 84 g of water
moles of NaOH =16/40
=0.4
moles of water =84/18
= 4.667
Total moles = 0.4+4.667
= 5.067
mole fraction of NaOH = 0.4/5.067
= 0.0789
Conclusion:
84 g water will have 0.4 moles of NaOH
1000g water will have [0.4x 1000]/84
= 4.76 moles
This is called molality.
ENJOY :)
</span>
Answer:
Explanation:
Hello,
In this case, since the percent abundance of Br-79 is 51.1% and that of the Br-81 is 48.9 %, we can write:
Taking into account that the mass of bromine from the periodic table is 79.909 amu, the mass of Br-81 turns out:
Best regards.
OK so the answer will be that 2 3 4 5 are correct the first choice is incorrect.
First determine the molality of the solution. m = (w solute)/[(mm solute)(kg solvent)] -- mm means molar mass. So,
m = (14.7 g)/[(180 g/mol)(0.150 kg) =0.544 mol/kg = 0.544 m
Change in boiling point (∆t) = m x Kbp = (0.544 m)(0.512 °C/m) = 0.28°C
The solution will boil at 100.28°C at 1 atm.
the density if water is 1.00 g/ml and Kb= 0.512 C/m