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3 years ago

What is this equation problem 3n+16=7n

Mathematics

2 answers:

Monica [59]3 years ago

7 0

If you mean what is n, then n = 4

galben [10]3 years ago

7 0

So I'm pretty good at these, so I'll put it in the best detail I can. I'm guessing you need to solve for n.

So here's your problem:
3n+16=7n

First off, you should switch it around so you don't have to deal with negatives:
7n=3n+16

Subtract 3n from both sides:
4n=16

Divide both sides by 4
n=4

That would be your answer, n=4. Hope this helps, have a wonderful day!

(brainliest is always appreciated)

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Answer:

We would save $1.52 cents

Step-by-step explanation:

3 the pencil were at sale for 25 cent

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5 the pencil were at sale for 29 cent

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3 years ago

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2 years ago

Find the distance between the complex numbers. z1 = 9 - 9i z2 = 10 - 9i

steposvetlana [31]

Answer:

The distance between the two given complex numbers = 9

Step-by-step explanation:

Explanation:-

Step(i):-

Given Z₁ = 9 - 9 i and Z₂ = 10 -9 i

Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane

⇒ A = Z₁ = x₁ +i y₁ = 9 - 9 i and

B = Z₂ = x₂+ i y₂ = 10 -9 i

Let (x₁ , y₁) = ( 9, -9)

(x₂, y₂) = (10, -9)

Step(ii):-

The distance between the two points are

A B = $\sqrt{(x_{2} - x_{1})^{2}+(y_{2} - y_{1})^{2} }$

A B = $\sqrt{(10 - 1)^{2}+(-9 - (-9))^{2} }$

AB = $\sqrt{(9)^{2} +(-9+9)^{2} }$

AB = √81 = 9

Conclusion:-

The distance between the two given complex numbers = 9

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2 years ago

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