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LekaFEV [45]
3 years ago
10

A car traveling north with the velocity of 30m/s slows down to a velocity of 10m/s within 10 seconds what is the cars accelerati

on
Physics
1 answer:
Andre45 [30]3 years ago
4 0

Average acceleration is what would be calculated her since there is a change in velocity.

Average acceleration = Change in velocity/Elapsed time

=(10 - 30)/10

= -20/10

= -2 m/s²

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A wall that is 12 feet wide and 10 feet high is to be painted. A blackboard that is 5 feet wide and 3 feet high is affixed to th
levacccp [35]

Answer:

The area of the portion of the wall that will be painted is 105 square feet

Explanation:

Total area of wall = 12 × 10 = 120 ft²

The area of the wall that will not be painted = area of the blackboard = 5 × 3 = 15 ft²

So, the area of the wall to be painted = Total area of wall - Area of the wall that will not be painted = 120 - 15 = 105 ft²

4 0
4 years ago
Un carro de montaña rusa parte del reposo desde una primera cumbre, desciende una distancia vertical de 45 metros y luego sube u
garri49 [273]
A roller coaster car starts from the rest from a first summit, descends a vertical distance of 45 meters and then climbs a second summit, reaching the top with a speed of 15m / s. How high is the second summit? Do not consider friction


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3 years ago
Why can you see you r reflection on a smooth pond but not on a rushing river
kolezko [41]
<span>because A rough surface, such as this rippling pond, causes light rays to bounce off it in many different directions. It may still be possible to make out an image on the surface, or, if it is very rough, the image is very broken up. Most objects reflect light in this irregular way. Although we can see them, we cannot see any images reflected in their surfaces.</span>
7 0
3 years ago
A sphere of metal has a mass of 1431 g and a diameter of 5.80 cm. What is the density of metal in g/cm3
Dmitriy789 [7]

Answer:

see below

Explanation:

You will need t find the volume of the sphere

 4/3 pi r^3    divide into the mass

1431 / (4/3 pi (5.8)^3) = 14 gm /cm^3

4 0
3 years ago
The charge on any negatively charged oil droplet is always a whole-number multiple of the fundamental charge of a single electro
shusha [124]

Answer:

1.6\times 10^{-18} C  

Explanation:

The fundamental charge of a single electron is 1.6\times 10^{-19} C.

If there are 10 excess electrons, the net charge that would be measured should be 10 times the fundamental charge of a single electron:

Q=nq_e\\Q= 10\times 1.6\times 10^{-19} C\\Q= 1.6 \times 10^{-18} C

3 0
3 years ago
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