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riadik2000 [5.3K]
4 years ago
14

Which statement best defines a morpheme?

Physics
2 answers:
skad [1K]4 years ago
8 0
The answer is c.

If we check our definitions in our notes, we can remember that it is the smallest part broken down in a word that provides meaning. 
IrinaVladis [17]4 years ago
8 0

Answer:

The correct option is ; 'It is the smallest unit of language that provides meaning.'

Explanation:

Morpheme is defined as the smallest word with a meaning within an other word that too in the same language.These words can stand alone as a word.

For example : In word 'pantry' there is small words like; 'pan', 'try' , 'ant'.

You might be interested in
A long, nonconducting cylinder (radius = 6.0 mm) has a nonuniform volume charge density given by αr2, where α = 6.2 mC/m5 and r
erastovalidia [21]

Answer: 2.80 N/C

Explanation: In order to calculate the electric firld inside the solid cylinder

non conductor we have to use the Gaussian law,

∫E.ds=Q inside/ε0

E*2πrL=ρ Volume of the Gaussian surface/ε0

E*2πrL= a*r^2 π* r^2* L/ε0

E=a*r^3/(2*ε0)

E=6.2 * (0.002)^3/ (2*8.85*10^-12)= 2.80 N/C

5 0
4 years ago
Choose the 200 kg refrigerator. set the applied force to 400 n (to the right). be sure friction is turned off. what is the net f
Firlakuza [10]

The net force acting on the refrigerator is 400 N to the right.

<h3></h3><h3>FURTHER EXPLANATION</h3>

The net force or resultant force is the sum of all the forces acting on a body or an object in x and y axes.

  • Forces along the y-axis The forces that usually act on an object vertically (in the y-axis) are: gravitational force which is a downward force and the normal force which is an upward (perpendicular) force exerted by a surface on an object resting above it that keeps the object from falling.
  • Forces along the x-axis These include the force or forces applied to cause a left or right motion of an object along the horizontal plane (called the Applied Force) and the force that opposes the motion or friction.

In this problem the forces acting on the x and y - axes can be determined:

Along the x-axis:

  • gravitational force = -1960 N
  • normal force = +1960 N
  • Net force = -1960 N + 1960 N = 0

The gravitational force is the weight of the object obtained by multiplying the mass of the object (in kg) with the acceleration due to gravity, 9.8 m/s^2. It is given a negative (-) sign to indicate that it is a downward force.

Since the object is not falling through the surface, it can be assumed that the gravitational force and normal force are balanced. Hence, the size of the normal force is the same as the gravitational force but with the opposite direction indicated by the + sign for an upward force.

The forces along the x-axis are balanced  (i.e. net force is zero) so the object neither moves upward or downward.

Along the y-axis

  • applied force = +400 N
  • friction = 0
  • Net force = +400 N + 0 = +400 N

The applied force is +400 N. It is given a + sign to indicate that its direction is to the right.

The friction, as mentioned in the problem, is set to zero or "turned off".

The net force along the y-axis is +400. The forces are unbalanced so the object will move to the right as force is applied to it.

<h3>LEARN MORE</h3>
  • Balanced Forces brainly.com/question/760473
  • Unbalanced Forces brainly.com/question/4289010
  • Free body Diagrams brainly.com/question/12345810

Keywords: net force, resultant force

5 0
4 years ago
Read 2 more answers
c) If the ice block (no penguins) is pressed down even with the surface and then released, it will bounce up and down, until fri
eduard

Answer:

y = 20.99 V / A

there is no friction    y = 20.99 h

Explanation:

Let's solve this exercise in parts: first find the thrust on the block when it is submerged and then use the conservation of energy

when the block of ice is submerged it is subjected to two forces its weight  hydrostatic thrust

         

              F_net= ∑F = B-W

the expression stop pushing is

              B = ρ_water g V_ice

where rho_water is the density of pure water that we take as 1 10³ kg / m³ and V is the volume d of the submerged ice

We can write the weight of the body as a function of its density rho_hielo = 0.913 10³ kg / m³

             W = ρ-ice g V

              F_net = (ρ_water - ρ_ ice) g V

this is the net force directed upwards, we can find the potential energy with the expression

            F = -dU / dy

            ΔU = - ∫ F dy

            ΔU = - (ρ_water - ρ_ ice) g ∫ (A dy) dy

            ΔU = - (ρ_water - ρ_ ice) g A y² / 2

we evaluate between the limits y = 0,  U = 0, that is, the potential energy is zero at the surface

             U_ice = (ρ_water - ρ_ ice) g A y² / 2

now we can use the conservation of mechanical energy

starting point. Ice depth point

             Em₀ = U_ice = (ρ_water - ρ_ ice) g A y² / 2

final point. Highest point of the block

             Em_{f} = U = m g y

as there is no friction, energy is conserved

            Em₀ = Em_{f}

            (ρ_water - ρ_ ice) g A y² / 2 = mg y

let's write the weight of the block as a function of its density

            ρ_ice = m / V

            m = ρ_ice V

we substitute

             (ρ_water - ρ_ ice) g A y² / 2 = ρ_ice V g y

              y = ρ_ice / (ρ_water - ρ_ ice) 2 V / A

let's substitute the values

             y = 0.913 / (1 - 0.913) 2 V / A

             y = 20.99 V / A

This is the height that the lower part of the block rises in the air, we see that it depends on the relationship between volume and area, which gives great influence if there is friction, as in this case it is indicated that there is no friction

                V / A = h

where h is the height of the block

                 y = 20.99 h

7 0
4 years ago
PLEASE HELP!!! Nico uses wire to connect a battery, a lightbulb, and a switch, but the bulb does not light up. Which might expla
Wewaii [24]
Its is C the answer is c lol
6 0
3 years ago
Read 2 more answers
 A hotdog cannon shoots a hotdog straight up in the air with an initial velocity of 30 m/s. How high will the hotdog fly?
Yuri [45]

At its peak height, the hotdog will have no vertical velocity, so that

{v_f}^2-{v_i}^2=2(-g)\Delta y\implies-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}

\implies y_{\mathrm{max}}=46\,\mathrm m

7 0
3 years ago
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