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Oksanka [162]
3 years ago
6

When Marie sees the red traffic light, Marie brakes to a halt from a speed of 70 m/s in just 2 seconds. What is her deceleration

?
Physics
1 answer:
SashulF [63]3 years ago
7 0

Answer:

-35 m/s^2

Explanation:

<u>Deceleration is the complete opposite of acceleration and is calculated by adding a negative sign to the formula for finding acceleration.</u>

Since acceleration is calculated by diving the change in velocity with time, deceleration will become:

 Deceleration =   -Δv/t, where Δv = change in velocity and t = time

In this case, Δv = 70 m/s and t = 2 s, hence;

Deceleration = -70/2 = -35 m/s^2

<em>The deceleration is 35 </em>m/s^2<em>.</em>

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3. Which vehicle has more momentum? *
AysviL [449]

Answer:

the one with v = 25 m/s

Explanation:

Momentum = m * v

 if they both have the same mass (15000 kg) , then the one with the higher v has more momentum...I think A= 25 m/s

5 0
2 years ago
What is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.13?
IgorLugansk [536]

Let us assume that pulley is mass less.

Let the tension produced at both ends of the pulley is T.

We are asked to calculate the acceleration of the block.

Let the masses of two bodies are denoted as m_{1} \ and\ m_{2}\ respectively

Let\ m_{1} =1 kg\ and\ m_{2} =2 kg

As per this diagram, the body having mass 1 kg is moving downward and the body having mass 2 kg is moving on the surface of the table.

Let the acceleration of each block is a .

For body having mass 1 kg:

The net force acting on 1 kg body will be-

                             m_{1} g-T=m_{1} a        [1]

Here tension in the rope will be vertically upward and weight of the body will be in vertical downward direction.

For body having mass 2 kg:

The coefficient of kinetic friction [\mu]=0.13

Hence\ the\ frictional\ force\ F=\mu N

                                                     F=\mu m_{2} g

Hence the net force acting on the body having mass 2 kg-

                                  T-\mu m_{2} g=m_{2} a  [2]

Here the tension of the rope is towards right i.e along the direction of motion of the 2 kg block and frictional force is towards left.

Combining 1 and 2 we get-

                           m_{1} g-T=m_{1}a             [1]

                           T-\mu m_{2}g= m_{2} a   [2]

                           ---------------------------------------------------

                           [m_{1} -\mu m_{2} ]g=[m_{1} +m_{2} ]a

                           a=\frac{m_{1}-\mu m_{2}} {m_{1}+ m_{2}}*g

                           a=\frac{1-[2*0.13]}{1+2} *9.8\ m/s^2

                           a=\frac{0.74}{3} *9.8\ m/s^2

                           a=2.417 m/s         [ans]

6 0
3 years ago
Read 2 more answers
How does the kinetic energy of an object relate to its mass and velocity?
Setler [38]

The kinetic energy of an object is directly proportional to its mass, and to the square of its velocity.

5 0
3 years ago
The AB rope is fixed to the ground at its A end, and forms 30º with the vertical. Its other end is connected to two ropes by mea
lana66690 [7]

Answer:

T = 80√3 N ≈ 139 N

W = 160 N

Explanation:

Sum of forces on B in the x direction:

∑F = ma

80 N sin 60° − T sin 30° = 0

T = 80 N sin 60° / sin 30°

T = 80√3 N

T ≈ 139 N

Sum of forces on B in the y direction:

∑F = ma

80 N cos 60° + T cos 30° − W = 0

W = 80 N cos 60° + T cos 30°

W = 40 N + 120 N

W = 160 N

6 0
3 years ago
Example of kinetic to potential ? And how the energy is changing forms???? Please help
faust18 [17]

Answer:

A ball when from moving to stoping

Explanation:

Kinetic = energy of motion

Potential = energy stored

When you roll a ball on the ground, it gains kinetic energy, but then the ball starts to slow down until it stops and it remains at rest which means it's at potential energy. It went from moving (kinetic) to stoping (potential)

Hope this helped!

Have a supercalifragilisticexpialidocious day!

8 0
3 years ago
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