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3 years ago

What is kinetic energy of 6 kg bowling ball if it is going 6.1 m/s

Physics

1 answer:

weqwewe [10]3 years ago

7 0

Answer:111.63 joules

Explanation:

Kinetic energy=(massx(velocity)^2)/2

Kinetic energy=(6×(6.1)^2)/2

Kinetic energy=(6×37.21)/2

Kinetic energy=223.26/2

Kinetic energy=111.63 joules

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Suppose that the average speed (vrms) of carbon dioxide molecules (molar mass 44.0 g/mol) in a flame is found to be 2.67 105 m/s

34kurt

Answer:

$T = 1.26 \times 10^8 K$

Explanation:

As we know that rms speed of ideal gas is given by the formula

$v_{rms} = \sqrt{\frac{3RT}{M}}$

here we know that

$v_{rms} = 2.67 \times 10^5 m/s$

molecular mass of gas is given as

$M = 44 g/mol = 0.044 kg/mol$

now from above formula we have

$2.67\times 10^5 = \sqrt{\frac{3(8.31)T}{0.044}}$

now we have

$T = 1.26 \times 10^8 K$

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3 years ago

You are driving your car at a speed of 60 miles per hour, when you cross into Canada. Canada measures their speed in kilometers

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Answer:

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3 years ago

Which standing wave has four antibodies?

frez [133]

Answer:

Term (symbol) Meaning

Standing wave Waves which appear to be vibrating vertically without traveling horizontally. Created from waves with identical frequency and amplitude interfering with one another while traveling in opposite directions.

Node Positions on a standing wave where the wave stays in a fixed position over time because of destructive interference.

Antinode Positions on a standing wave where the wave vibrates with maximum amplitude.

Fundamental frequency Lowest frequency of a standing wave that has the fewest number of nodes and antinodes.

Harmonic A standing wave that is a positive integer multiple of the fundamental frequency.

Explanation:

7 0

3 years ago

What is the average rate of change for this exponential function for the interval from x = 2 to x= 4 ?

irina [24]

The answer is D. 6 . This is because it is a positive slope so you can cancel out B and C and then, you count your boxes

8 0

3 years ago

Read 2 more answers

A 1,492.3-kg airplane travels down the runway. Each of its four engines provides a force of

Fittoniya [83]

The acceleration of the air plane is $3.879 \mathrm{m} / \mathrm{s}^{2}$

<u>Explanation:</u>

Given:

The mass of the air plane = 1492.3 kg

Force of each four engine = 1447.5 N

So, the total force of four engines can be calculated as = 4(1447.5) = 5790 N

The force that acts on the object is equal to the product of mass (m) and its acceleration. It can express by the below formula,

$\text {Force }(F)=m \times \text { acceleration }(a)$

The above equation can be written as below to find acceleration,

$a=\frac{F}{m}$

Now. Substitute the given values, we get,

$a=\frac{5790}{1492.3}=3.879 \mathrm{m} / \mathrm{s}^{2}$

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3 years ago