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ICE Princess25 [194]
3 years ago
12

length of a rectangle is 3 times its width.If its perimeter is 24 centimetres what is the area of the rectangle?​

Mathematics
2 answers:
fgiga [73]3 years ago
7 0

Answer:

<h3>27 cm²</h3>

Step-by-step explanation:

The length is 3 × width.

l = 3w

The perimeter is 24 centimeters.

P = 2l + 2w

24 = 2(3w) + 2w

24 = 6w + 2w

24 = 8w

3 = w

The width is 3 centimeters.

l = 3(3)

l = 9

The length is 9 centimeters.

Area is l × w.

A = l × w

A = 9 × 3

A = 27

The area is 27 squared centimeters.

natali 33 [55]3 years ago
5 0

Answer:

27

Width= x

Length= x × 3 =3x

so, 3x+3x+x+x=24

8x=24

x=24/8

x=3

so, length=3(3)=9

width=3

therefore,

Area=9×3

=27

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The Sharks have played 5 basketball games this seasons. Their scores are 65,63,67,60, and 65. If they only score 30 points in th
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3 years ago
Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
IrinaK [193]

Answer:

1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that \mu = 6.6, \sigma = 1.1

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

Z = \frac{X - \mu}{\sigma}

-2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = -2.41*1.1

X = 3.95

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

The 100 - 0.8 = 99.2nd percentile, which is X when Z has a p-value of 0.992, so X when Z = 2.41.

Z = \frac{X - \mu}{\sigma}

2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = 2.41*1.1

X = 9.25

The maximum head breadth that will fit the clientele is of 9.25-in.

8 0
2 years ago
Circle has a radius of 25 ft which of the following values is closest to the area of the circle in square feet a 80 B 160 C 310
Marina CMI [18]
To find the area that is the closest, use the formula for finding the area of a circle.

A = pi x r^2
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This is closest to answer choice D.
4 0
3 years ago
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