Question

Find the equation of a circle that has its center at (-4, 3) and has a radius of 5. (x + 4) 2 + (y - 3) 2 = 25

Answer 1

Answer:

$(x+4)^2 + (y-3)^2 = 25$

Step-by-step explanation:

You can use the center of a circle to write an equation in vertex form. Vertex form is $(x-h)^2+(y-k)^2 = r^2$ and the vertex is (h,k). Notice (h,k) are the opposite sign in the equation then as the point.

Here h = -4 and k = 3. Substitute these values and the value r = 5.

$(x--4)^2 + (y-3)^2 = 5^2\\(x+4)^2 + (y-3)^2 = 25$