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Vadim26 [7]
3 years ago
15

What is 32.15 in unit form??

Mathematics
2 answers:
tekilochka [14]3 years ago
4 0
3 tens, 2 ones, 1 tenth, 5 hundredths
Llana [10]3 years ago
3 0

Answer:

3 tens, 2 ones, 1 tenths and 5 hundredths.

Step-by-step explanation:

We are asked to write 32.15 in unit form.

To write 32.15 in unit form, we need to write each digit as its place value.

Ones: 2

Tens: 3

Tenths: 1

Hundredths: 5

Therefore, 32.15 in unit form would be 3 tens, 2 ones, 1 tenths and 5 hundredths.

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<h2>Answer:</h2>

a. \ g^{-1}=-1 \pm\sqrt{\frac{3}{x}+1}

<h2>Step-by-step explanation:</h2>

A function has an inverse function if and only if passes the Horizontal Line Test for Inverse Functions. This test tells us that a function f has an inverse function if and only if there is no any horizontal line that intersects the graph of f at more than one point. So the function is called one-to-one. The graph of g is shown below. As you can see, this function does not pass the Horizontal Line Test, therefore the inverse is not a function. However, let's find g^-{1}(x):

g(x)=\frac{3}{x^2+2x} \\ \\ Substitute \ g(x) \ by \ y \\ \\y=\frac{3}{x^2+2x} \\ \\ Interchange \ x \ and \ y: \\ \\ x=\frac{3}{y^2+2y} \\ \\ Solve \ for \ y: \\ \\y^2+2y=\frac{3}{x} \\ \\ Completing \ square \\ \\y^2+2y\mathbf{+ 1}\mathbf{-1}=\frac{3}{x} \\ \\(y+1)^2=\frac{3}{x}+1 \\ \\y+1=\pm\sqrt{\frac{3}{x}+1} \\ \\ y=-1 \pm\sqrt{\frac{3}{x}+1}

Finally, substitute y \ by \ g^{-1}:

boxed{g^{-1}=-1 \pm\sqrt{\frac{3}{x}+1}}

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