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Vadim26 [7]
4 years ago
15

What is 32.15 in unit form??

Mathematics
2 answers:
tekilochka [14]4 years ago
4 0
3 tens, 2 ones, 1 tenth, 5 hundredths
Llana [10]4 years ago
3 0

Answer:

3 tens, 2 ones, 1 tenths and 5 hundredths.

Step-by-step explanation:

We are asked to write 32.15 in unit form.

To write 32.15 in unit form, we need to write each digit as its place value.

Ones: 2

Tens: 3

Tenths: 1

Hundredths: 5

Therefore, 32.15 in unit form would be 3 tens, 2 ones, 1 tenths and 5 hundredths.

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PLSSSSSSSSSSSSSSSSSSSSSSSSSS ANSWER THIS
postnew [5]

Step-by-step explanation:

(a.y^{3} +3y^{2} -3 ) = (ay^{2} +(4a+3)y +4(4a+3))(y-4) +64a+45

so A = 64a +45

(2y^{3} -5y+a =(2y^{2} +8y +27)(y-4) +108 +a

so B = 108 +a

2A-B=0--> 2(64a+45)-108-a=0--> a =18/127

7 0
3 years ago
True or False ? A remainder of 1 or more in the process of doing synthetic division tells you that you have found a root of the
coldgirl [10]

Answer:

False

Step-by-step explanation:

If the value is a root of the polynomial, then the remainder will be 0. This means that the root as a factor will multiply to make the polynomial.

7 0
3 years ago
Read 2 more answers
What's the digit in the tenths place ​
Darya [45]
Tenths is the digit in the tenths place. Like 0.1 being 1 tenth.
5 0
3 years ago
Please help
nalin [4]

Answer:

12870ways

Step-by-step explanation:

Combination has to do with selection

Total members in a tennis club = 15

number of men = 8

number of women = 7

Number of team consisting of women will be expressed as 15C7

15C7 = 15!/(15-7)!7!

15C7 = 15!/8!7!

15C7 = 15*14*13*12*11*10*9*8!/8!7!

15C7 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2

15C7  = 15*14*13*12*11/56

15C7 = 6,435 ways

Number of team consisting of men will be expressed as 15C8

15C8 = 15!/8!7!

15C8 = 15*14*13*12*11*10*9*8!/8!7!

15C8 = 15*14*13*12*11*10*9/7 * 6 * 5 * 4 * 3 * 2

15C8 = 6,435 ways

Adding both

Total ways = 6,435 ways + 6,435 ways

Total ways = 12870ways

Hence the required number of ways is 12870ways

4 0
3 years ago
One of the factors of 34 is chosen at random. What is the probability that the factor is itself a two digit number?
solong [7]
A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?

The positive whole-number factors of 30 are:

1, 2, 3, 5, 6, 10, 15 and 30.

So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that

P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors

=38=3×.125=.375
8 0
3 years ago
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