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2 years ago

Find the circumference of the pizza to the nearest tenth.

Mathematics

1 answer:

mote1985 [20]2 years ago

7 0

Answer:

C=2πr

r=D/2=10/2=5

C=2×3.14×5

C=31.4in

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Find the missing term of the arithmetic sequence 17,____,23

Kruka [31]

Answer:20

Step-by-step explanation:

17 + 3 = 20

20 + 3 = 23

8 0

3 years ago

Deon rented a truck for one day there was a base fee of $19.99 and there was an additional charge of 98 cents for each mile driv

scZoUnD [109]

Answer:

Deon drove the truck 201 miles.

Step-by-step explanation:

Base Fee + (.98* Number of miles)= Cost

19.99 + .98x = 216.97

Subtract 19.99 from both sides.

.98x = 196.98

Divide both sides by .98

x = 201

5 0

3 years ago

Either enter an exact answer in terms of \piπpi or use 3.14, point, 14 for \piπpi and enter your answer as a decimal.

OverLord2011 [107]

Answer:

49π sq. units

Step-by-step explanation:

Find the diagram attached

We can find the area of the given circle

Given

diameter of the circle d = 14

Area of the circle = πd²/4

Substitute the given diameter

Area of the circle = π(14)²/4

Area of the circle = 196π/4

Area of the circle = 49π sq. units

Hence the exact answer in terms of π is 49π sq. units

4 0

2 years ago

What is 4r + 3r + 7y + 5r - 2y - 6r ? A. 5r + 5y B. 29r - 27y C. 27ry

Sonja [21]

Step-by-step explanation:

It's 6r+5y. But it's not in the option

3 0

2 years ago

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

6 0

2 years ago