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3 years ago

I need help someone pleassssseeeee

Mathematics

2 answers:

KengaRu [80]3 years ago

7 0

Your answer is B, hope I helped :)

lys-0071 [83]3 years ago

3 0

The answer would be B.

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harina [27]

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2.04

Step-by-step explanation:

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viktelen [127]

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The caplan family was going to New York City to ring in the New Year. 16 family members each paid $341 for their plane ticket to

Usimov [2.4K]

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3 years ago

I am having trouble finding this out will anyone help?

dalvyx [7]

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3 years ago

The locations:

GREYUIT [131]

The quadrilateral is a trapezoid and the area of the quadrilateral is 85.04 square units

<h3>How to determine the quadrilateral?</h3>

The vertices are given as:

A:(-2, 3) B:(4, -6) C:(10, 2) D:(6, 8)

Next, we plot the vertices (see attachment)

From the attached graph, we can see that the quadrilateral is a trapezoid

<h3>How to determine the area?</h3>

From the plot, we have the following features:

Height: AD

Parallel sides: CD and AB

Calculate the lengths using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

So, we have:

$AD = \sqrt{(-2 -6)^2 + (3 -8)^2}$

$AD = \sqrt{89}$

$CD = \sqrt{(10 -6)^2 + (2 -8)^2}$

$CD = \sqrt{52}$

$AB = \sqrt{(-2 -4)^2 + (3 +6)^2}$

$AB = \sqrt{117}$

The area is then calculated as:

Area = 0.5 * (CD + AB) * AD

This gives

Area = 0.5 * (√52 + √117) * √89

Evaluate

Area = 85.04

Hence, the area of the quadrilateral is 85.04 square units