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madam [21]
3 years ago
7

What unit is electrical energy typically measured in on energy bills?

Physics
2 answers:
velikii [3]3 years ago
6 0
Electricity<span> is </span>measured<span> in </span>units<span> of power called Watts</span>
Sav [38]3 years ago
5 0

It is kilowatt-hours. The other answer is half wrong.

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Joe is camping in the mountains when a storm suddenly hits. Joe hears the thunder and sees the lightning. A lightning strike sta
svp [43]

Answer:

Hypothalamus

Explanation:

Dealing with a storm is a stressful situation especially when the fire has started in the forest. These multiple signals are processed by hypothalamus that is located in the base of the brain and send the processed information to Pitutary gland that makes primary secretions to activate the renal medulla and a fight-or-flight response to stimuli is generated by rushing the body with energy induced by Adrenaline

8 0
3 years ago
1) If you release a rubber band that had 10 units of elastic energy, 12 units of movement energy cannot be produced. Why not?
Mila [183]

Answer:

press dat crown for meh

Explanation:

4 0
3 years ago
Read 2 more answers
A boy on a 1.9 kg skateboard initially at rest tosses a(n) 7.8 kg jug of water in the forward direction. if the jug has a speed
Tresset [83]
For this case we first think that the skateboard and the child are one body.
 We have then:
 1 = jug
 2 = skateboard + boy
 By conservation of the linear amount of movement:
 M1V1i + M2V2i = M1V1f + M2V2f
 Initial rest:
 v1i = v2i = 0
 0 = M1V1f + M2V2f
 Substituting values
 0 = (7.8) (3.2) + (M2) (- 0.65)
 0 = 24.96 + M2 (-0.65)
 -24.96 = (-0.65) M2
 M2 = (-24.96) / (- 0.65) = 38.4 kg
 Then, the child's mass is:
 M2 = Mskateboard + Mb
 Clearing:
 Mb = M2-Mskateboard
 Mb = 38.4 - 1.9
 Mb = 36.5 Kg
 answer:
 the boy's mass is 36.5 Kg
4 0
3 years ago
A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T.
Gekata [30.6K]

As per the question, the point charge is given as [q] = 6.8 C

The velocity of the charged particle [v] = 6.5*10^{4}\ m/s

The magnetic field [B] = 1.4 T

The angle made between magnetic field and velocity [\theta] = 15 degree.

We are asked to calculate the magnetic force experienced by the charged  particle.

The magnetic force experienced by the charged particle is calculated as -

Magnetic force \vec F=q(\ \vec V \times \vec B)

                        i.e F = =qVBsin\theta

                                   =6.8*6.5*10^{4}*1.4*sin15

                                   =61.88*10^{4}sin15

                                   =61.88*10^4*0.2588\ N

                                   =16.016*10^4\ N

                                   =1.6*10^5\ N

Hence, the force experienced by the charged particle is C i.e 1.6*10^5 N

                                   

             

4 0
3 years ago
Read 2 more answers
An anchor with a density of 700 lb/ft3 tied to a rope is submerged in water (but is not touching the bottom). It has a volume of
Ivanshal [37]

Answer:

Explanation:

Given

Density of anchor \rho _a=700\ lb/ft^3

Volume of anchor V=2.8\ ft^3

Density of water \rho _w=62.4\ lb\ft^3

Buoyancy force on submerged object is given by

F_B=\rho _W\times V\times g

F_B=62.4\times 2.8\times 32.2=5625.98\approx 5626\ approx lbf          

3 0
3 years ago
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