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lesya [120]
3 years ago
8

1) If you release a rubber band that had 10 units of elastic energy, 12 units of movement energy cannot be produced. Why not?

Physics
2 answers:
Mila [183]3 years ago
4 0

Answer:

press dat crown for meh

Explanation:

Aleksandr-060686 [28]3 years ago
4 0

Answer:

Look Below

Explanation:

1. Because the initial energy is 10 J

2. The rubber band would lose the energy upon release

3. not sure but i think its mechanical energy

I learnt these all 1 year ago so idk for sure

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First law of equilibrium
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For an object to be an equilibrium it must be experiencing no acceleration.

Explanation:

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The higher the voltage across a bulb the b__________ it is.
podryga [215]

Answer:

Brighter

Explanation:

8 0
3 years ago
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Why are metals good conductors of both heat and electricity?
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They are both good conductors if both heat and electricity due to the sea of delocalized electrons that is floating around without getting bonded to an atom.

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Two difference between thrust and upthrust .
velikii [3]

Upthrust is the upward force exerted by fluids on the surface of an object immersed in fluids. Thrust:- It is the force acting perpendicular to the surface. Upthrust:- It is the upward force exerted by the fluid on the surface of an object immersed in liquid.

I hope it's help you

6 0
3 years ago
Several large firecrackers are inserted into the holes of a bowling ball, and the 6.3 kg ball is then launched into the air with
Anni [7]

Answer

given,

mass of the ball = 6.3 kg

speed of the ball = 10.4 m/s

angle made with horizontal = 43°

m_a = 1.8 kg               v_a = 2.2 m/s

m_b = 1.6 kg               v_b = 1.8 m/s

mass of third particle = 6.3 - 1.8 - 1.6

                                   = 2.9 kg

u cos θ = 10.4 x cos 43° = 7.61 m/s

by using conservation momentum along x-axis

6.3 x 7.61 = 1.8 × (-2.2) + 0 + 1.6 × V₃ₓ

V₃ₓ = 32.44 m/s (toward right)

by using conservation momentum along y-axis

0 = 0 + 1.6 x 1.8 + 1.6 × V₃y

V₃y = -1.8 m/s (indicate downward)

velocity of the third particle

v = \sqrt{32.44^2 + (-1.8)^2}

v = 32.49 m/s

tan \theta = \dfrac{-1.8}{32.44}

\theta = tan^{-1}(\dfrac{-1.8}{32.44})

θ = 3.176° (downward with horizontal)

4 0
3 years ago
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