All categories

3 years ago

1) If you release a rubber band that had 10 units of elastic energy, 12 units of movement energy cannot be produced. Why not?

Physics

2 answers:

Mila [183]3 years ago

4 0

Answer:

press dat crown for meh

Explanation:

Aleksandr-060686 [28]3 years ago

4 0

Answer:

Look Below

Explanation:

1. Because the initial energy is 10 J

2. The rubber band would lose the energy upon release

3. not sure but i think its mechanical energy

I learnt these all 1 year ago so idk for sure

You might be interested in

What is the device used to detect and measure current?

dybincka [34]

The Ammeter is used to detect and measure current or amperage. Also a more common tool now used is a multimeter that detects and measures voltage, current, and resistance.

Any questions please just ask. Thank you.

6 0

3 years ago

Read 2 more answers

Two engineering students, John with a weight of 92 kg and Mary with a weight of 46 kg, are 30 m apart. Suppose each has a 0.04%

Hoochie [10]

Answer:

F = 6.27 x 10 ¹⁹ N

Explanation:

Given

m₁ = 92 kg, m₂ = 46 kg, % = 0.04% N = 6.022 x 10²³ Z = 18, e = 1.6 x 10 ⁻¹⁹ C, M = 0.018 kg/mol

q₁ = % * [m * N * A * e / M ]

q₁ = 0.0004 * [ ( 92 kg * 6.022 x 10²³ * 18 * 1.6 x 10 ⁻¹⁹ ) / (0.018 kg/mol ) ]

q₁ = 3.54 x 10⁶ C

q₂ = 0.0004 * [ ( 46 kg * 6.022 x 10²³ * 18 * 1.6 x 10 ⁻¹⁹ ) / (0.018 kg/mol ) ]

q₂ = 1.773 x 10⁶ C

Now to determine the electrostatic force con use the equation

F = K * q₁ * q₂ / d²

K = 8.99 x 10 ⁹

F = 8.99 x 10 ⁹ * 3.54 x 10⁶ C * 1.773 x 10⁶ C / (30m)²

F = 6.27 x 10 ¹⁹ N

3 0

3 years ago

What is most likely the author’s motive for writing this article? to get you to buy sports products to get you to support nuclea

harina [27]

To get you to aooreciate the benefits of atomic reaserch

i know this cause i just had the question and i got it right

4 0

3 years ago

Read 2 more answers

Problems - Show all work.

Fittoniya [83]

Answer:

21s

Explanation:

Given parameters;

Radius = 10m

Speed or velocity = 3m/s

Unknown:

Period = ?

Solution:

To solve this problem, use the expression:

v = $\frac{2\pi r}{T}$

r is the radius

T is the unknown

Input the parameters and solve for T;

3 = $\frac{2 x \pi x 10}{T}$

62.84 = 3T

T = 21s

4 0

3 years ago

The Orion nebula is one of the brightest diffuse nebulae in the sky (look for it in the winter, just below the three bright star

Oxana [17]

Answer:

T=183.21K

Explanation:

We have to take into account that the system is a ideal gas. Hence, we have the expression

$PV=nRT$

where P is the pressure, V is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant.

Thus, it is necessary to calculate n and V

V is the volume of a sphere

$V=\frac{4}{3}\pi r^3=\frac{4}{3}\pi (5.9*10^{15}m)^3=8.602*10^{47}m^3$

V=8.86*10^{50}L

and for n

$n=\frac{(4000M_s)/(2*mH)}{6.022*10^{23}mol^{-1}}=3.95*10^{36}mol$

Hence, we have (1 Pa = 9.85*10^{-9}atm)

$T=\frac{PV}{nR}=\frac{(6.8*10^{-9}*9.85*10^{-6}atm)(8.86*10^{50}L)}{(0.0820\frac{atm*L}{mol*K})(3.95*10^{36}mol)}\\\\T=183.21K$

hope this helps!!

8 0

3 years ago