If a quadrilateral is a parallelogram, then its opposite sides are _____.

1 answer:

3 0

The answer is letter c.

<span>If a quadrilateral is a parallelogram, then its opposite sides are congruent. The congruence is the result of the Euclidean parallel postulate.

</span>

<span>Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.</span>

You might be interested in

A stock quote is advice from a broker about what stock to invest in. True or False?

Len [333]

The Answer Is False. A Stock Quote Provides Information Such As The Bid & Ask Price, Last-Traded Price, Etc.

3 0

3 years ago

Help me with this please. And kid please leave me alone cuz I didn't take your points ._.

weeeeeb [17]

Answer:

step 3 addition: 20 + 9 = 29

step 4 subtraction: 29 - 2 = 27

solution 27

Step-by-step explanation:

since there's no more multiplication or division, you add and subtract from left to right

8 0

3 years ago

The dimensions of a closed rectangular box are measured as 60 centimeters, 50 centimeters, and 70 centimeters, with an error in

Studentka2010 [4]

Answer:

The maximum error in calculating the surface area of the box is 72 square centimeters.

Step-by-step explanation:

From Geometry, the surface area of the closed rectangular box ( $A_{s}$ ), in square centimeters, is represented by the following formula:

$A_{s} = w\cdot l + (w + l)\cdot h$ (1)

Where:

$w$ - Width, in centimeters.

$l$ - Length, in centimeters.

$h$ - Height, in centimeters.

And the maximum error in calculating the surface area ( $\Delta A_{s}$ ), in square centimeters, is determined by the concept of total differentials, used in Multivariate Calculus:

$\Delta A_{s} = \left(l+h\right)\cdot \Delta w + \left(w+h\right)\cdot \Delta l + (w+l)\cdot \Delta h$ (2)

Where:

$\Delta w$ - Measurement error in width, in centimeters.

$\Delta l$ - Measurement error in length, in centimeters.

$\Delta h$ - Measurement error in height, in centimeters.

If we know that $\Delta w = \Delta h = \Delta l = 0.2\,cm$ , $w = 60\,cm$ , $l = 50\,cm$ and $h = 70\,cm$ , then the maximum error in calculating the surface area is: