Answer:
Connect the arcs to make a perpendicular bisector
A^2+b^2=c^2 so c^2=12^2+16^2 which then simplifies to c^2=144+256 then simplify that to c^2=400. After that take the square root of c^2 and the square root of 400. So your answer is c=20
It looks like they're multiplied, then you can simply add the exponents,
b⁸ * b⁴ = b⁸⁺⁴ = b¹²
remember, b⁸=b*b*b*b*b*b*b*b and b⁴=b*b*b*b
so b⁸ * b⁴ = b*b*b*b*b*b*b*b * b*b*b*b = b¹²
Answer:
(4, 7)
Step-by-step explanation:
The midpoint formula is (((x1 + x2)/2), ((y1+y2)/2)))
x1 +x2 = 1 +7 = 8
8/2 = 4
y1 + y2 = 10 + 4 = 14
14/2 = 7
(4, 7) is the midpoint
Answer:
![\boxed{\sf -2n+20}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20-2n%2B20%7D)
Step-by-step explanation:
Let’s find the common difference.
The common difference can be found by subtracting a term in the sequence with the previous term.
![\sf d=16-18\\d=-2](https://tex.z-dn.net/?f=%5Csf%20d%3D16-18%5C%5Cd%3D-2)
Apply formula for the
term of an arithmetic sequence.
![\sf a_n=a_1+dn-d](https://tex.z-dn.net/?f=%5Csf%20a_n%3Da_1%2Bdn-d)
is the first term of the sequence.
is the common difference.
![\sf a_n=18+-2n-(-2)](https://tex.z-dn.net/?f=%5Csf%20a_n%3D18%2B-2n-%28-2%29)
![\sf a_n=18+-2n+2](https://tex.z-dn.net/?f=%5Csf%20a_n%3D18%2B-2n%2B2)
![\sf a_n=-2n+20](https://tex.z-dn.net/?f=%5Csf%20a_n%3D-2n%2B20)