What is the point-slope form of a line that has a slope of 3 and passes through point (1, 4)? y minus 4 = 3 (x minus 1) 1 minus
2 answers:
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<em>x = -4 is a vertical asymptote for the function.</em>
<h2>Explanation:</h2>The graph of is a vertical has an asymptote at
if at least one of the following statements is true:
The function is:
First of all, let't factor out:
From here:
Accordingly:
Vertical and horizontal asymptotes: brainly.com/question/10254973
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Answer: AAA similarity.
Step-by-step explanation: CB is the transversal for the parallel lines AB and DE, and so by transverse property, we have ∠CED ≅ ∠CBA. Similarly, CA acts as a tranversal for the same pair of parallel lines AB and DE and using the same property, we can have ∠CDE ≅ ∠CAB. Now, in triangles CED and ABC, we have
∠CED ≅ ∠CBA,
∠CDE ≅ ∠CAB
and
∠DCE ≅ ∠ACB [same angle]
Hence, by AAA (angle-angle-angle) similarity,
△CED ~ △ABC.
Thus, the correct option is AAA similarity.
