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3 years ago

11

How many grams of NH3 are needed to provide the same number of molecules as in 0.55 grams of SF6?

1 answer:

xenn [34]3 years ago

4 0

Above it says the molecular weights are

NH3- 17g/mol and SF6-146 g/mol

Well 1 mole of SF6 is 146.048 grams (i added hte atomic masses of each element). So then the number of moles in 0.85 grams would be 0.00582000438 moles.

<span><span>= 1mole / 146.048g *</span> 0.85g</span>

so we would need 0.00582000438 moles of NH3 to have the same number of molecules.

One mole of NH3 is 17.030519999989988 grams (i added each atoms mass). so 0.00582000438 moles of NH3 would be:

<span><span>= 17.030519999989988 g / mole * </span>0.00582000438moles</span>

that equals 0.09911770099 grams.

so 0.09911770099 grams is the answer if you rounded, you get about 0.1 grams

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2 years ago

16. The concentration of a solution of potassium hydroxide is determined by titration with nitric

____ [38]

Answer:

$M_{base}=0.709M$

Explanation:

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In this case, since the reaction between potassium hydroxide and nitric acid is:

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3 0

3 years ago

PLEASE ANSWER ASAP

kodGreya [7K]

Answer:It is C i got it correct

Explanation:

7 0

3 years ago

Butane (C4 H10(g), mc031-1.jpgHf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , mc031-2.jpgHf = –393.5 kJ/

ankoles [38]

The balanced chemical equation for the combustion of butane is:

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= $[{8*(-393.5kJ/mol)}+{10*(-241.82kJ/mol)}]-[{2*(-125.6kJ/mol)}+13*(0 kJ/mol)}]$ =[-3148kJ/mol+(-2418.2kJ/mol)]-[(-251.2kJ/mol)+0]

= -5315 kJ/mol

Calculating the enthalpy of combustion per mole of butane:

$1mol C_{4}H_{10}*( \frac{-5315kJ}{2mol C_{4}H_{10} })=-2657.5 \frac{kJ}{molC_{4}H_{10}}$

Therefore the heat of combustion per one mole butane is -2657.5 kJ/mol

Correct answer: -2657.5 kJ/mol

6 0

2 years ago

Please help me, also I have other unanswered questions similar to this one if you can help I'd greatly appreciate it. got until

mart [117]

Answer:

C. Br and Cl

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A covalent bond forms between non-metals.
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The electronegativity difference between the species must be very low or zero.
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7 0

2 years ago

Read 2 more answers