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Tom [10]
3 years ago
7

What is the orbital or electronic geometry of a molecule with 0 nonbonding electron pairs and 2 bonding electron pairs?

Chemistry
1 answer:
disa [49]3 years ago
3 0
Linear is the answer
You might be interested in
Number 14 please help.. chemistry
Zolol [24]

Taking into account the definition of density, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Mass of the substance in this case</h3>

In this case, you know that:

  • Density= 1.5 \frac{g}{cm^{3} }
  • Volume= 150 cm³

Replacing in the definition of density:

1.5 \frac{g}{cm^{3} } =\frac{mass}{150 cm^{3} }

Solving:

mass= 1.5 \frac{g}{cm^{3} }  ×150 cm³

<u><em>mass= 225 g</em></u>

In summary, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

#SPJ1

7 0
2 years ago
Which of the following equations are balanced?
Ber [7]

Answer:

I think the first one

Explanation:

I'm not really sure but i count it

3 0
3 years ago
What is the estimated effective nuclear charge, Z eff, experienced by an electron in a 3p orbital of a chlorine atom?
mojhsa [17]
Effective nuclear charge is the charge felt by valence electrons of multi-electron atom taking into consideration the number of shielding electrons that surround the nucleus.
To calculate Z eff for electron we use this formula :
Z eff = Z - S where Z is the number of protons in nucleus and S is the average amount of electron density between the nucleus and electron in consideration
so Z eff = 17 - 10 (core electrons) = 7 
So the correct answer is C 
6 0
4 years ago
the isotope 146c has a half life of 5730 years. what fraction of 146c in a sample with mass ,m, after 28650 years
defon

Answer:

3.1% is the fraction of the sample after 28650 years

Explanation:

The isotope decay follows the equation:

Ln[A] = -kt + Ln[A]₀

<em>Where [A] could be taken as fraction of isotope after time t, k is decay constant and [A]₀ is initial fraction of the isotope = 1</em>

<em />

k could be obtained from Half-Life as follows:

K = Ln 2 / Half-life

K = ln 2 / 5730 years

K = 1.2097x10⁻⁴ years⁻¹

Replacing in isotope decay equation:

Ln[A] = -1.2097x10⁻⁴ years⁻¹*28650 years + Ln[1]

Ln[A] = -3.4657

[A] = 0.0313 =

<h3>3.1% is the fraction of the sample after 28650 years</h3>

<em />

3 0
3 years ago
Please help!
hammer [34]
The answer is B) Electrons flow from negitive end to positive end because opposites attract
7 0
3 years ago
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