The answer is covalent bonding. Molecular compounds are made of 2 or more nonmetals, and are therefore covalent. That is why another name for "molecular compound" is "covalent compound".
Answer: (1) covalent bonding
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<h3><u>Answer;</u></h3>
HCl and KCl
<h3><u>Explanation</u>;</h3>
- Strong electrolytes are strong bases and acids.
- HCl is a strong acid; it dissociates completely to form H+ and Cl- ions. Thus, it is a strong, rather than weak, electrolyte.
- CH3COOH is acetic acid, a weak acid. Only some of it will dissociate (to H+ and acetate ions), thus, it will only be a weak electrolyte.
- NH3 will react with water as a weak base: NH3 + H2O → NH4+ + OH-. It will thus also be a weak electrolyte.
- KCl is a soluble ionic compound, and as such, it will be a strong electrolyte.
Answer:
Mass = 12.276 g
Explanation:
Given data:
Number of molecules of H₂S = 2.16 × 10²³
Mass in gram = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
Number of moles of H₂S:
2.16 × 10²³ molecules × 1 mole /6.022 × 10²³ molecules
0.36 moles
Mass = number of moles × molar mass
Mass = 0.36 mol × 34.1 g/mol
Mass = 12.276 g
Answer:
It is important for scientists to form a consensus on scientific issues because scientific consensus tells us things that we have already learned.
Answer:
The correct option is: provide a source of counterions to prevent the build-up of charge at both the cathode to the anode.
Explanation:
A salt bridge is a U-shaped glass tube that is used in a voltaic cell or galvanic cell to connect the oxidation and reduction half-cells and complete the electric circuit.
<em>It allows the ions to pass through it, thus preventing the accumulation of charge on the anode and cathode as the chemical reaction proceeds.</em>
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Therefore, the correct option is: <u>provide a source of counterions to prevent the build-up of charge at both the cathode to the anode.</u>
