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3 years ago

11

5) More heat will flow outside on a cold day because of:

2 answers:

densk [106]3 years ago

7 0

Answer:

The Sun

Explanation:

The Sun Because The Sun May Be Big And Will Cause To Make The Cold Warm

Softa [21]3 years ago

6 0

Hotter things have more heat energy than colder things. That's because the atoms or molecules move around faster in hot things (red, right) than they do in cold things (blue, left). This idea is called the kinetic theory.

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The "steady state theory" suggested that the universe has always existed and maintains the same structure,

erastovalidia [21]

The steady state theory was discredited by the discovery of cosmic background radiation.

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4 years ago

A net force of 1 newton causes an object to accelerate at a rate of 5.0 meters per second per second. What is the mass of the ob

Nadya [2.5K]

Mass = force / acceleration = 1/5 = 0.2 Kg

4 0

3 years ago

A bead of mass 15g is sliding on a wire. It has a speed of 2.0m/s at A, and it stops as it reaches the point C. The length of th

umka2103 [35]

Answer:

.12 N

Explanation:

Velocity goes from 2 m/s to 0 m/s so average velocity = 1 m/s

.250 m / 1 m/s = .25 second to stop

change in velocity / change in time = accel

2 m/s / .25 sec = 8 m/s^2

F = ma

= .015 kg * 8 m/s^2 = .12 N

7 0

1 year ago

Which statement best describes who the period and frequency of electromagnetic was change between gamma rays and microwaves?

nalin [4]

Answer : <em> The period increases and the frequency decreases</em>.

Explanation :

Gamma rays are the rays having frequency( $\nu$ ) greater than $10^{19}\ Hz$ and frequency of microwave lie between 300 MHz to 300 GHz.

Since, $E=h\nu$

So, as we move from gamma rays to microwaves the energy increases because frequency is increasing.

Also, Time period $T=\dfrac{1}{\nu}$

We can say that as the time period increases, frequency decreases.

6 0

3 years ago

Read 2 more answers

Water moves through a constricted pipe in steady, ideal flow. At the

Irina-Kira [14]

A) Speed in the lower section: 0.638 m/s

B) Speed in the higher section: 2.55 m/s

C) Volume flow rate: $1.8\cdot 10^{-3} m^3/s$

Explanation:

A)

To solve the problem, we can use Bernoulli's equation, which states that

$p_1 + \rho g h_1 + \frac{1}{2}\rho v_1^2 = p_2 + \rho g h_2 + \frac{1}{2}\rho v_2^2$

where

$p_1=1.75\cdot 10^4 Pa$ is the pressure in the lower section of the tube

$h_1 = 0$ is the heigth of the lower section

$\rho=1000 kg/m^3$ is the density of water

$g=9.8 m/s^2$ is the acceleration of gravity

$v_1$ is the speed of the water in the lower pipe

$p_2$ is the pressure in the higher section

$h_2 = 0.250 m$ is the height in the higher pipe

$v_2$ is hte speed in the higher section

We can re-write the equation as

$v_1^2-v_2^2=\frac{2(p_2-p_1)+\rho g h_2}{\rho}$ (1)

Also we can use the continuity equation, which state that the volume flow rate is constant:

$A_1 v_1 = A_2 v_2$

where

$A_1 = \pi r_1^2$ is the cross-section of the lower pipe, with

$r_1 = 3.00 cm =0.03 m$ is the radius of the lower pipe (half the diameter)

$A_2 = \pi r_2^2$ is the cross-section of the higher pipe, with

$r_2 = 1.50 cm = 0.015 m$ (radius of the higher pipe)

So we get

$r_1^2 v_1 = r_2^2 v_2$

And so

$v_2 = \frac{r_1^2}{r_2^2}v_1$ (2)

Substituting into (1), we find the speed in the lower section:

$v_1^2-(\frac{r_1^2}{r_2^2})^2v_1^2=\frac{2(p_2-p_1)+\rho g h_2}{\rho}\\v_1=\sqrt{\frac{2(p_2-p_1+\rho g h_2)}{\rho(1-\frac{r_1^4}{r_2^4})}}=0.638 m/s$

B)

Now we can use equation (2) to find the speed in the lower section:

$v_2 = \frac{r_1^2}{r_2^2}v_1$

Substituting

v1 = 0.775 m/s

And the values of the radii, we find:

$v_2=\frac{0.03^2}{0.015^2}(0.638)=2.55 m/s$

C)

The volume flow rate of the water passing through the pipe is given by

$V=Av$

where

A is the cross-sectional area

v is the speed of the water

We can take any point along the pipe since the volume flow rate is constant, so

$r_1=0.03 cm$

$v_1=0.638 m/s$

Therefore, the volume flow rate is

$V=\pi r_1^2 v_1 = \pi (0.03)^2 (0.638)=1.8\cdot 10^{-3} m^3/s$

Learn more about pressure in a liquid:

brainly.com/question/9805263

#LearnwithBrainly

0 0

3 years ago