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Setler [38]
3 years ago
8

a dart player throws a dart at speed of 12.9m/s. the dart hits the board 0.35m below the height from which it was theown. how fa

r away is the player from the board?​

Physics
1 answer:
Veseljchak [2.6K]3 years ago
3 0
1. Find the amount of time the dart is in the air using the equation dy...
2. Vy initial is 0, and the only force acting on the dart while it is in the air is gravity so the acceleration of the dart in the y direction is 9.8.
3. Plug in the time you found and Vx = 12.9 to get Dx

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A flat screen is located 0.63 m away from a single slit. Light with a wavelength of 550 nm (in vacuum) shines through the slit a
s2008m [1.1K]

Answer:

1.308 * 10^(-5) m

Explanation:

We apply the condition for a single slit experiment:

y = (λ * D) / a

Where y = half width of fringe

λ = wavelength of light

D = distance of slit from screen

a = width of slit

We need to find a, so we make a the subject of formula:

a = (λ * D) / y

From the question:

λ = 550 nm = 550 * 10^(-9) m

D = 0.63 m

y = 0.053 / 2 = 0.0265 m

Therefore:

a = (550 * 10^(-9) * 0.63) / 0.0265

a = 1.308 * 10^(-5) m

The width of the slit is 1.308 * 10^(-5) m

5 0
3 years ago
If an object looks blue, it reflects ____ waves.
soldi70 [24.7K]
It reflects blue light waves.
7 0
3 years ago
A copper rod 81 cm long is used to poke a fire. the hot end of the rod is maintained at 105° c and the cool end has a constant t
Ugo [173]
The temperature inside the copper rod varies linearly with the distance from the hot end of the rod. This means that we can find the temperature at 23 cm (let's call it 'point A') from the cool end by solving a linear proportion.

The temperature difference between the two ends of the rod is
\Delta T = 105^{\circ}-21^{\circ} = 84^{\circ}
and this corresponds to a length of 81 cm. Therefore, we can write:
84^{\circ}:81~cm = x:23~cm
from which we find
x=23.8~^{\circ}
This is not the final answer actually; this is the temperature difference between the cool end and point A. So, the temperature at point A is
T_A = 21^{\circ}+x=44.8^{\circ}
7 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
EleoNora [17]

The basketball is gaining kinetic and losing potential energy is the answer


8 0
3 years ago
Read 2 more answers
The battery for a certain cell phone is rated at 3.70 V. According to the manufacturer it can produce math]3.15 \times 10^{4} J[
AysviL [449]

Answer:

The average current that this cell phone draws when turned on is 0.451 A.

Explanation:

Given;

voltage of the phone, V = 3.7 V

electrical energy of the phone battery, E = 3.15 x 10⁴ J

duration of battery energy, t = 5.25 h

The power the cell phone draws when turned on, is the rate of energy consumption, and this is calculated as follows;

P = \frac{E}{t}

where;

P is power in watts

E is energy in Joules

t is time in seconds

P = \frac{3.15*10^4}{5.25*3600s} = 1.667 \ W

The average current that this cell phone draws when turned on:

P = IV

I = \frac{P}{V} =\frac{1.667}{3.7} = 0.451 \ A

Therefore, the average current that this cell phone draws when turned on is 0.451 A.

5 0
3 years ago
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