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Setler [38]
3 years ago
8

a dart player throws a dart at speed of 12.9m/s. the dart hits the board 0.35m below the height from which it was theown. how fa

r away is the player from the board?​

Physics
1 answer:
Veseljchak [2.6K]3 years ago
3 0
1. Find the amount of time the dart is in the air using the equation dy...
2. Vy initial is 0, and the only force acting on the dart while it is in the air is gravity so the acceleration of the dart in the y direction is 9.8.
3. Plug in the time you found and Vx = 12.9 to get Dx

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Newton's third law can be summarized as "every action has an equal and opposite reaction". In this problem, consider the action
scoundrel [369]

Answer:

Action force: Would be the force of your feet against the Earth given by the weight defined as:

W = mg

Where g is a constat who represent the gravity g =9.8 m/s^2 in Earth

Reaction force: Would be the force of the Earth pushing against your feet. And on this case is represented by the normal force defined as:

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Where \mu represent the friction coefficient between the ground and the object.

And f_f the friction force.

If we don't have any other forces involved in the y axis we can conclude that:

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And as we can see we have that Action force = Reaction force

So then the third Law of Newton is satisfied.

Explanation:

For this case we have this:

Action force: Would be the force of your feet against the Earth given by the weight defined as:

W = mg

Where g is a constat who represent the gravity g =9.8 m/s^2 in Earth

Reaction force: Would be the force of the Earth pushing against your feet. And on this case is represented by the normal force defined as:

N = \mu f_f

Where \mu represent the friction coefficient between the ground and the object.

And f_f the friction force.

If we don't have any other forces involved in the y axis we can conclude that:

W=N= mg

And as we can see we have that Action force = Reaction force

So then the third Law of Newton is satisfied.

7 0
3 years ago
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