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myrzilka [38]
3 years ago
6

The driver of a pickup truck going 89.9 km/h applies the brakes giving the truck a uniform deceleration of 5.99 m/s^2 while it t

ravels 19.3 m.
a. The velocity of the truck in m/s at the end of this displacement is
_________ m/s.
b. How much time has elapsed?
_________s
Physics
1 answer:
mel-nik [20]3 years ago
6 0

(a) First, convert the truck's velocity from km/h to m/s:

89.9\,\dfrac{\mathrm{km}}{\mathrm h}\cdot\dfrac{10^3\,\mathrm m}{\mathrm{km}}\cdot\dfrac{\mathrm h}{3600\,\mathrm s}=25.0\,\dfrac{\mathrm m}{\mathrm s}

Then the velocity v after traveling \Delta x=19.3\,\mathrm m satisfies

v^2-{v_0}^2=2a\Delta x

where v_0 and a are the truck's initial velocity and acceleration, respectively. So we have

v^2-\left(25.0\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-5.99\,\dfrac{\mathrm m}{\mathrm s^2}\right)(19.3\,\mathrm m)

\implies v^2=394\,\dfrac{\mathrm m^2}{\mathrm s^2}

\implies v=\pm19.8\,\dfrac{\mathrm m}{\mathrm s}

Taking the square root gives two possible velocities of the same magnitude but in opposite directions. It's technically feasible that over the given displacement, the truck changes its direction and is accelerating back towards its starting position since we're treating the truck as a particle.

(b) When acceleration is constant, average velocity is given by

v_{\mathrm{av}}=\dfrac{x-x_0}t=\dfrac{v+v_0}2

which tells us that

t=\dfrac{2(19.3\,\mathrm m)}{v+25.0\,\frac{\mathrm m}{\mathrm s}}

Plugging in both possible values of v we found earlier, we get t=0.862\,\mathrm s (if v is positive) or t=7.42\,\mathrm s (if v is negative).

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Light of wavelength 580 nm is incident on a slit of width 0.30 mm. An observing screen is placed 2.0 m past the slit. Find the d
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Explanation:

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Y = \frac{\lambda L}{d}

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Y = fringe spacing = ?

L = slit to screen distance = 2 m

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Y = \frac{(5.8\ x\ 10^{-7}\ m)(2\ m)}{3\ x\ 10^{-4}\ m}

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Hope this helps


7 0
3 years ago
Read 2 more answers
7. How long does it take a ball rolling down a hill to change its speed from 3 m/sec to 34.5 m/sec
lys-0071 [83]

The time elapsed is 9 seconds

Explanation:

The motion of the ball is a uniformly accelerated motion (a motion with constant acceleration), so we can use the following suvat equation:

v=u+at

where :

v is the final velocity  of the ball

u is the initial velocity

a is the acceleration

t is the time  elapsed

For the ball in this problem, we have:

u = 3 m/s is the initial velocity

v = 34.5 m/s is the final velocity

a=3.5m/s^2 is the acceleration

Solving for t, we find the time taken for this change in velocity:

t=\frac{v-u}{a}=\frac{34.5-3}{3.5}=9 s

Learn more about acceleration:

brainly.com/question/9527152  

brainly.com/question/11181826  

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brainly.com/question/2562700  

#LearnwithBrainly

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