Its going more horizontal because the slope has you go up 1 and right 4, meaning you are going right more than you are going up
Answer:
For this case we need to check the conditions in order to use the normal approximation:
1) ![np = 60*0.3= 18>10](https://tex.z-dn.net/?f=np%20%3D%2060%2A0.3%3D%2018%3E10)
2) ![n(1-p) = 60*(1-0.3)= 42>10](https://tex.z-dn.net/?f=n%281-p%29%20%3D%2060%2A%281-0.3%29%3D%2042%3E10)
Since both conditions are satisfied and the independence condition is assumed we can use the normal approximation given by:
![\hat p \sim N (\hat p, \sqrt{\frac{\hat p(1-\hat p)}{n}})](https://tex.z-dn.net/?f=%5Chat%20p%20%5Csim%20N%20%28%5Chat%20p%2C%20%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%29)
The mean would be given by:
![\mu_{\hat p}=0.3](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%20p%7D%3D0.3)
And the deviation is given by:
![\sigma_{\hat p}= \sqrt{\frac{0.3*(1-0.3)}{60}}= 0.0592](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%20p%7D%3D%20%5Csqrt%7B%5Cfrac%7B0.3%2A%281-0.3%29%7D%7B60%7D%7D%3D%200.0592)
Step-by-step explanation:
For this case we know the following info:
n =60 represent the sample size
represent the estimated proportion of people that will buy a packet of crackers after tasting
For this case we need to check the conditions in order to use the normal approximation:
1) ![np = 60*0.3= 18>10](https://tex.z-dn.net/?f=np%20%3D%2060%2A0.3%3D%2018%3E10)
2) ![n(1-p) = 60*(1-0.3)= 42>10](https://tex.z-dn.net/?f=n%281-p%29%20%3D%2060%2A%281-0.3%29%3D%2042%3E10)
Since both conditions are satisfied and the independence condition is assumed we can use the normal approximation given by:
![\hat p \sim N (\hat p, \sqrt{\frac{\hat p(1-\hat p)}{n}})](https://tex.z-dn.net/?f=%5Chat%20p%20%5Csim%20N%20%28%5Chat%20p%2C%20%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%29)
The mean would be given by:
![\mu_{\hat p}=0.3](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%20p%7D%3D0.3)
And the deviation is given by:
![\sigma_{\hat p}= \sqrt{\frac{0.3*(1-0.3)}{60}}= 0.0592](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%20p%7D%3D%20%5Csqrt%7B%5Cfrac%7B0.3%2A%281-0.3%29%7D%7B60%7D%7D%3D%200.0592)
Answer:
95°
Step-by-step explanation:
Since, quadrilateral DUCK is inscribed in circle O
sum of the opposite angles of the quadrilateral is 180°
m<K +m<U= 180°
m<K= 180°- 85°= 95°
Answer:
c. (-2, 2)
Step-by-step explanation:
that's where the lines intersect, at the point (-2, 2)