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Tasya [4]
3 years ago
15

(9x - 4x2 + 9) + (-x3 + 4x2 - 3)

Mathematics
2 answers:
Schach [20]3 years ago
8 0

Answer:

- x^{3\\} + 9x + 6

Step-by-step explanation:

First, you need to combine like terms. Like terms, when dealing with exponents can be categorized by their powers.

hIn this case, 9x stands alone, because there is no other coefficient with the power of just x.

9x

Next, we can look at the -4x^2. The other similar coefficient is + 4x^2. We can combine both of those, which will equal out to 0.

Next, you have 9. It can be combined with -3, since none of them have an exponent attached. It will equal 6

9x + 6

We also have a -x^3 left over. There is no like term to combine with it, so we can leave it as is.

Our problem now looks like

9x + 6 - x^{3}

You can rearrange them in the proper order, so it will look like,

- x^{3} + 9x + 6.

And there you have it!

____ [38]3 years ago
5 0

Answer:

The solution to the given expression is -x³ + 9x + 6

Step-by-step explanation:

(9x - 4x² + 9) + (-x³ + 4x² - 3)

Since there is a positive sign in front of the second parentheses, then the terms inside will stay the same.

9x - 4x² + 9 - x³ + 4x² - 3

Group terms together that are alike. Also known as like terms.

-x³ + (-4x² + 4x²) + 9x + (9 - 3)'

Combine like terms.

-x³ + 9x + 6

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For questions 2-5, the number of pieces in a regular bag of Skittles is approximately normally distributed with a mean of 38.4 a
aleksley [76]

Answer:

a. -1.60377

b. 0.25451

c. 0.344

d. Option b) 78th

Step-by-step explanation:

The number of pieces in a regular bag of Skittles is approximately normally distributed with a mean of 38.4 and a standard deviation of 2.12.

a)What is the z-score value of a randomly selected bag of Skittles that has 35 Skittles? a) 1.62 b) -1.62 c) 3.40 d) -3.40 e)1.303.

The formula for calculating a z-score is is z = (x-μ)/σ,

where x is the raw score

μ is the population mean

σ is the population standard deviation.

z = 35 - 38.4/2.12

= -1.60377

Option b) -1.62 is correct

b) What is the probability that a randomly selected bag of Skittles has at least 37 Skittles? a) .152 b) .247 c) .253 d).747e).7534. .

z = (x-μ)/σ

Mean of 38.4 and a standard deviation of 2.12.

z = (37 - 38.4)/2.12

= -0.66038

P-value from Z-Table:

P(x<37) = 0.25451

The probability that a randomly selected bag of Skittles has at least 37 Skittles is 0.25451

Option c) .253 is.correct

c) What is the probability that a randomly selected bag of Skittles has between 39 and 42 Skittles? a) .112 b) .232 c) .344 d).457 e).6125.

z = (x-μ)/σ

Mean of 38.4 and a standard deviation of 2.12.

For 39 Skittles

z = (39 - 38.4)/2.12

= 0.28302

Probability value from Z-Table:

P(x = 39) = 0.61142

For 42 Skittles

z = (42 - 38.4)/2.12

= 1.69811

Probability value from Z-Table:

P(x = 42) = 0.95526

The probability that a randomly selected bag of Skittles has between 39 and 42 Skittles is:

P(x = 42) - P(x = 39

0.95526 - 0.61142

0.34384

= 0.344

Option c is.correct

d) What is the percentile rank of a randomly selected bag of Skittles that has 40 Skittles in it? a)82nd b) 78th c) 75th d)25th e)22nd

z = (x-μ)/σ

Mean of 38.4 and a standard deviation of 2.12.

z = (40 - 38.4)/2.12

= 0.75472

P-value from Z-Table:

P(x = 40) = 0.77479

Converting to percentage = 0.77479× 100

= 77. 479%

≈ 77.5

Percentile rank = 78th

7 0
3 years ago
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USPshnik [31]
Answer)
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