Answer:
Your supposed to cancel out 12 on both sides so u subtract 12 on both sides so the equation would be
-3x= -52
Step-by-step explanation:
9514 1404 393
Answer:
- (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
- NOT linearly independent
Step-by-step explanation:
We want ...
c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0
Substituting for the fn function values, we have ...
c1·x +c2·x² +c3·(2x -4x²) ≡ 0
This resolves to two equations:
x(c1 +2c3) = 0
x²(c2 -4c3) = 0
These have an infinite set of solutions:
c1 = -2c3
c2 = 4c3
Then for any parameter t, including the "trivial" t=0, ...
(c1, c2, c3) = (-2t, 4t, t)
__
f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)
Answer:
D: t = u/9 + 7 (that is simplified all of the way) for your case it is t = u + 63/9 so D
Explanation:
Just ask if you need an explanation. Also, does anyone do LD debate?
A. (x+8)^ 2 + 1
B. (x-3)^ 2 - 8
C. ( x - 3/2) ^ 2 - 1/4
