1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ExtremeBDS [4]
2 years ago
8

Is it necessary to use the formulas for special products of binomials to multiply these binomials?

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
5 0
Idk ISO idk idk so yes likeblots
You might be interested in
In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

7 0
3 years ago
Round this whole number Round 10,652 to the nearest ten.
ValentinkaMS [17]

Answer:

10650

Step-by-step explanation:

3 0
3 years ago
How does graphing -3/4 different from graphing 3/4
katovenus [111]
Graph 1: y= -3/4, which means its (x,y) coordinate is (0, -3/4).

Graph 2: y= 3/4, which means its (x,y) coordinate is (0, 3/4).

Graph 1 would be the point -3/4 on the y-axis, while graph 2 would be the point 3/4 on the y-axis.

Therefore, graph 1 and graph 2 are symmetrical about the x-axis.

Hope this would help~
3 0
3 years ago
- The two rectangles shown have equal areas. Find the value of x.
Anna [14]
X= 36 I think

Hope this helps
4 0
3 years ago
HELP PLZ I NEED TO PASS LESSON
Ierofanga [76]

Step-by-step explanation:

452

8 0
3 years ago
Other questions:
  • Morgan scored 42 points in 3 games. How many points would you expect him to make in an 11 game season?
    14·2 answers
  • a bag contains a-r-I-t-h-m-e-t-I-c. Amelia chooses a tile without looking and doesn’t replace it. She chooses a second tile with
    15·2 answers
  • The difference between three times a number and seven is twenty. What is the number?
    14·1 answer
  • × + 3 = 7 show how you got the answer
    12·2 answers
  • Find the reference angle of the following angles:
    8·1 answer
  • By rounding to 1 significant figure, estimate the answers to these questions:<br><br> 346 x 904
    13·2 answers
  • Andrew withdrew $332.55 from his savings account. He now has at most $529.71. How Much cash did he originally have?
    11·1 answer
  • Help! geometry <br><br> find the arc length of the shaded sector <br><br> arc length = blank cm
    10·1 answer
  • Could someone please help me and fast?
    15·1 answer
  • Trapezoid TUVM is rotated 90 counterclockwise about the origin. After the rotation, what is the location of vertex V?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!