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3 years ago

What is 15/6 in mixed number

Mathematics

2 answers:

kogti [31]3 years ago

8 0

To write an improper fraction as a mixed number, divide the denominator into the numerator.

Image is provided.

Therefore, the improper fraction 15/6 can be written as the mixed number 2 and 3/6.

jenyasd209 [6]3 years ago

5 0

15/6 is an improper fraction.

Lets convert this into a proper fraction.

How many times does 6 go into 15?

6*2 = 12

Only twice, so our whole number is 2.

15-12 = 3

3 is our numerator.

2 3/6 = 2 1/2

Mixed number form: 2 1/2

Final answer: 2 1/2

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tia_tia [17]

The answer would be 1/6.

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3 years ago

The hospital shop buys cereal bars in packs of 4. In one day they sell 58 cereal bars. How many packets did they open tht day?

Vikentia [17]

They opened 15 boxes. you can tell that this is the answer because 58÷4=14.5 and you can't open half a box so you round up to 15

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2 years ago

What is the volume of a cone with a height of 10.5 inches and a radius of 8 inches? cone v = 1 3 bh 1. rewrite the formula for t

bonufazy [111]

The volume of the cone that has a radius of 8 in. and a height of 10.5 in. is: 703.7 in.³

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Volume = 1/3πr²h

Given the parameters:

Height (h) = 10.5 in.
Radius (r) = 8 in.

Volume of the cone = 1/3πr²h = 1/3π(8²)(10.5)

Volume of the cone = 1/3π(64)(10.5)

Volume of the cone = 703.7 in.³

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3 0

2 years ago

Read 2 more answers

A computer virus is trying to corrupt two files. The first file will be corrupted with probability 0.4. Independently of it, the

Ksivusya [100]

Answer:

$P(X = 0) = 0.42$

$P(X = 1) = 0.46$

$P(X = 2) = 0.12$

Step-by-step explanation:

We have these following probabilities:

40% probability that the first file is corrupted. So 60% probability that the first file is not corrupted.

30% probability that the second file is corrupted. So 70% probability that the second file is not corrupted.

Probability mass function

Probability of each outcome(0, 1 and 2 files corrupted).

No files corrupted:

60% probability that the first file is not corrupted.

70% probability that the second file is not corrupted.

$P(X = 0) = 0.6*0.7 = 0.42$

One file corrupted:

First one corrupted, second no.

40% probability that the first file is corrupted.

70% probability that the second file is not corrupted.

First one ok, second one corrupted.

60% probability that the first file is not corrupted.

30% probability that the second file is corrupted.

$P(X = 1) = 0.4*0.7 + 0.6*0.3 = 0.46$

Two files corrupted:

40% probability that the first file is corrupted.

30% probability that the second file is corrupted.

$P(X = 2) = 0.4*0.3 = 0.12$

8 0

2 years ago

A physical education teacher plans to divide the seventh graders at Wilson Middle School into teams of equal size of year-ending

Crank

Step-by-step explanation:

Consider the provided information.

The total number of students are: 24+26+21=71

He wants each team will have the same number of students between 5 and 9.

The number between 5 to 9 are 6, 7 and 8.

The number 71 is a prime number so we need to divide the 71 students in group so that minimum students left without team.

Dividing 6 students in each group.

Number of teams: $\frac{71}{6}$ = 11 teams and 5 students.

Dividing 7 students in each group.

Number of teams: $\frac{71}{7}$ = 10 teams and 1 students.

Dividing 8 students in each group.

Number of teams: $\frac{71}{8}$ = 8 teams and 7 students.

Thus, we can not divide 71 students into equal teams, but 70 divided by 7 gives the least students left out i.e 10 teams each with 7 students and only 1 student will remain at last.

6 0

3 years ago