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3 years ago

What is 15/6 in mixed number

Mathematics

2 answers:

kogti [31]3 years ago

8 0

To write an improper fraction as a mixed number, divide the denominator into the numerator.

Image is provided.

Therefore, the improper fraction 15/6 can be written as the mixed number 2 and 3/6.

jenyasd209 [6]3 years ago

5 0

15/6 is an improper fraction.

Lets convert this into a proper fraction.

How many times does 6 go into 15?

6*2 = 12

Only twice, so our whole number is 2.

15-12 = 3

3 is our numerator.

2 3/6 = 2 1/2

Mixed number form: 2 1/2

Final answer: 2 1/2

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2 years ago

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2 years ago

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Which of the following statements are correct? Select all that apply.

Marizza181 [45]

For a 7 sides polygon which is called heptagon or septagon
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3 years ago

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The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original

evablogger [386]

Here as the Pentagon is regular so it's all sides will be of equal length . And if we assume It's each side be s , then it's perimeter is going to be (s+s+s+s+s) = 5s.And as here , each side is increased by 8 inches and then it's perimeter is 65 inches , so we got that it's side after increament is (s+8) inches and original length is s inches . And if it's each side is (s+8) inches , so it's perimeter will be 5(s+8) and as it's equal to 65 inches . So , 5(s+8) = 65

${:\implies \quad \sf 5(s+8)=65}$

${:\implies \quad \sf 5s+5\times 8=65}$

${:\implies \quad \sf 5s+40=65}$

${:\implies \quad \sf 5s=65-40}$

${:\implies \quad \sf 5s=25}$

${:\implies \quad \sf s=\dfrac{25}{5}=5}$

${:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}$

As we assumed the original side to be s .

Hence, the original side's length 5 inches 

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1 year ago

1. The sum of the three consecutive members of the geometric sequence is 13. The proportion of the third and the first member is

aev [14]

If a = first term and r = common ratio we have

a + ar + ar^2 = 13 and ar^2 / a = r^2 = 9

so r = 3

and a + 3a + 9a = 13
so a = 1

so they are 1,3 and 9

2.
in geometric series we have

4 , 4r ,4r^2 , 60

Arithmetic;
4, 4r , 4r + d , 4r + 2d

so we have the system of equations
4r + 2d = 60
4r^2 = 4r + d
From first equation
2r + d = 30
so d = 30 - 2r
Substitute for d in second equation:-
4r^2 - 4r - (30-2r) = 0
4r^2 - 2r - 30 =0

2r^2 - r - 15 = 0
(r - 3)(2r + 5) = 0
r = 3 or -2.5
r must be positive so its = 3
and d = 30 - 2(3) = 24

and the numbers are 4*3 = 12 , 4*3^2 = 36

first 3 are 4 , 12 and 36 ( in geometric)
and last 3 are 12, 36 and 60 ( in arithmetic)

The 2 numbers we ause are 12 and 36.

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3 years ago