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Nana76 [90]
3 years ago
7

Julia rides her horse 12 miles in 45 minutes. What is her average speed in mi/min?

Physics
2 answers:
Maurinko [17]3 years ago
4 0

Answer:

0.266666667mi/1min

Explanation:

12 divided by 45 = 0.266666667

lesya [120]3 years ago
4 0

Answer:

0.26666666667mi/min

Explanation:

average speed of an object is the total distance traveled by the object divided by the elapsed time to cover that distance.

Av.speed=12miles/45mins

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The weight of a body kept at a distance of 6400 km from the centre of the
Vlad [161]

Answer:

2.5N

Explanation:

since force is inversely proportional to square of the distance apart. that means the ratio of distance apart. so u have 12800×12800÷(6400××6400)=4/1

so the weight will be reduced to 1/4 of 10N

6 0
3 years ago
In the picture below, label which particle is the solute and which is the solvent ​
klasskru [66]
The black circles are the solvent and the open circles are the solute
8 0
3 years ago
A car stops in 130 m. If it has an acceleration of -5 m/s2 what was the cars starting velocity?
Tatiana [17]

Answer:

<u>We are given:</u>

displacement (s) = 130 m

acceleration (a) = -5 m/s²

final velocity (v) = 0 m/s      [the cars 'stops' in 130 m]

initial velocity (u) = u m/s

<u>Solving for initial velocity:</u>

From the third equation of motion:

v² - u² = 2as

replacing the variables

(0)² - (u)² = 2(-5)(130)

-u² = -1300

u² = 1300

u = √1300

u = 36 m/s

8 0
3 years ago
Can someone please answer this, ill give you brainliest and your getting 100 points.
Nata [24]

Answer:

Point number 3.

Explanation:

Volcanism can be studied to found out evidence of the internal structure of the Earth.

6 0
2 years ago
Read 2 more answers
Calculate the number of free electrons and holes (in m-3) in an intrinsic semiconductor that has electron and hole mobilities of
allochka39001 [22]

Answer:

ni = 2.04e19

Explanation:

we know that in semiconductor like intrinsic, when electron leave the band, it leave a hole in valence band so we have

n = p = ni

from intrinsic carrier concentration

\sigma = n\left | e \right | \mu_e + n\left | e \right | \mu_h

\sigma = ni\left | e \right | \mu_e  + ni\left | e \right | \mu_h

\sigma = ni \left | e \right | ( \mu_e + \mu_h)

1.7 = ni * 1.6*10^{-19} * (.35 + .17)

ni = 2.014 *10^{19} m^{-3}

ni = 2.04e19

5 0
3 years ago
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