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elena55 [62]
3 years ago
8

How can you tell the difference between halite, calcite, and gypsum

Physics
1 answer:
ehidna [41]3 years ago
6 0
Halite is transparent, but it can be died many different colors calcite is a white or colorless mineral consisting of calcium carbonate. It is a major constituent of sedimentary rocks such as limestone, marble, and chalk, can occur in crystalline form gypsum is a soft white or gray mineral consisting of hydrated calcium sulfate.
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A sledgehammer hits a wall How do the hammer and the wall act on each other?
tigry1 [53]

We want to study the impact of a sledgehammer and a wall.

Before the sledgehammer hits the wall, it has a given velocity and a given mass, so it has momentum and it has kinetic energy.

When it hits the wall, the velocity of the hammer disappears, this means that the energy is transferred to the wall, this "transfer of energy" can be thought of a force applied for a really short time on the wall, which for the third law of Newton, the force is also applied on the hammer.

This is why you feel the impact on the handle when you hit something with a hammer, this also means that some of the energy is dissipated on your arms.

Now, because the wall is made of a material usually not as strong as the head of the sledgehammer, we will see that in this interaction the wall seems more affected than the hammer, but the forces that each one experiences are exactly equal in magnitude.

If you want to learn more, you can read:

brainly.com/question/13952508

7 0
3 years ago
on takeoff, the propellers on a uav (unmanned aerial vehicle) increase their angular velocity from rest at a rate of ω = (25.0t)
Rudik [331]

Hi there!

a)
We can find the angular velocity at t = 2.0 s by plugging in this value into the equation.

\omega (t) = 25.0t \\\\\omega (2) = 25.0(2) = \boxed{50.0 \frac{rad}{s}}

b)

The angular acceleration is the derivative of the angular velocity, so:
\alpha (t) = \frac{d\omega}{dt} (25.0t) = 25.0

Thus, the angular acceleration is a <u>constant 25 rad/s².</u>

7 0
2 years ago
A golfer hits her tee-shot due north towards the fairway. Her shot has an initial velocity of 60 m/s. A 15 m/s wind is blowing i
vovangra [49]

Answer:

c=71.4m/s

\theta=8.54\textdegree

Explanation:

From the question we are told that

Initial velocity of 60 m/s

Wind speed V_w= 15 m/s \angle  45 \textdegree

Generally Resolving vector mathematically

  sin(45\textdegree)15=10.6\\cos(45\textdegree)15=10.6

Generally the equation Pythagoras theorem is given mathematically by

c^2=a^2+b^2

c^2=10.6^2 +(10.6+60)^2

c=\sqrt{10.6^2 +(10.6+60)^2}

Therefore Resultant velocity (m/s)

c=71.4m/s

b)Resultant direction

Generally the equation for solving Resultant direction

\theta=tan^-1(\frac{y}{x})

Therefore

\theta=tan^-1(\frac{10.6}{70.6})

\theta=8.54\textdegree

7 0
3 years ago
How will gravitational wave discovery help the scientists in their quest to fully understand gravity?
irina [24]
<span>The heavier the body is, the stronger its gravitational pull. Just like earth, we feel gravitational pull because we are attracted to earth and so is the moon. Also, the sun is heavier than the earth and therefore, we are attracted to the sun because of its gravitational pull. When the earth revolves around the sun, both of them releases gravitational waves. Gravitational waves are ripples of waves travelling outward from the source. The more massive the orbit of two bodies, the more it emits gravitational wave. And everything around it that is near within the wave experiences a ‘pull’ toward the orbiting bodies. The advantages we get when we can measure gravitational waves are; one, we can measure the activity between two bodies in orbit in the universe, two, scientist can estimate the merging of two bodies in the universe every 15 minutes by using LIGO and three, we can know the behavior of other bodies that we did not know exist.</span>
8 0
4 years ago
If two negative charges of -2 C and -2 C are put 32,692 m apart from each other how much force will push them apart?
babunello [35]

Answer:

33.65 N

Explanation:

Force that will push them away is given from the equation;

F = Kq1•q2/r²

Where;

K is coulumbs constant = 8.99 × 10^(9) Nm²/C²

We are given;

q1 = q2 = -2 C

r = 32692 m

Thus;

F = 8.99 × 10^(9) × (-2) × (-2)/32692²

F ≈ 33.65 N

6 0
3 years ago
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