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VLD [36.1K]
3 years ago
11

A golfer wants his shot to land

Physics
1 answer:
scoray [572]3 years ago
5 0

Answer:

35.67 m/s

Explanation:

Applying the formular for range,

R = u²sin2∅/g....................... Equation 1

Where R = Range, u = Initial Velocity, ∅ = angle of launch, g = acceleration due to gravity

make u the subject of the equation

u = √(Rg/sin2∅)............. Equation 2

Given: R = 122 m, g = 9.8 m/s², ∅ = 55°

Substitute these values into equation 2

u = √[(122×9.8)/(sin(2×55))]

u = √(1195.6/sin110)

u = √(1272.33)

u = 35.67 m/s

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Two square air-filled parallel plates that are initially uncharged are separated by 1.2 mm, and each of them has an area of 190
julia-pushkina [17]

Answer:

5.5\cdot 10^{-11} C

Explanation:

The capacitance of the parallel-plate capacitor is given by:

C=\epsilon_0 \frac{A}{d}

where

\epsilon_0 = 8.85\cdot 10^{-12} F/m is the vacuum permittivity

A=190 mm^2 = 190 \cdot 10^{-6} m^2 is the area of the plates

d=1.2 mm = 0.0012 m is the separation between the plates

Substituting,

C=(8.85\cdot 10^{-12}) \frac{190 \cdot 10^{-6}}{0.0012}=1.4\cdot 10^{-12}F

The energy stored in the capacitor is given by

U=\frac{Q^2}{2C}

Since we know the energy

U=1.1 nJ = 1.1 \cdot 10^{-9} J

we can re-arrange the formula to find the charge, Q:

Q=\sqrt{2UC}=\sqrt{2(1.1\cdot 10^{-9} J)(1.4\cdot 10^{-12}F )}=5.5\cdot 10^{-11} C

8 0
3 years ago
Define alpha and beta​
elena55 [62]

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Answer:

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3 years ago
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Because it's literally impossible to tell exactly where something that size is
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