The time of fly of a projectile to the same level as it was launched is 2(v_y)/g=2(47sin(25))/g. We multiply this by the v_x to get the distance. Thus, the distance is <span>2(47sin(25))/g*47cos(25)=86.2. This is a overshoot!</span>
In accordance with the definition of density as r = m/V, in order to determine the density of
matter, the mass and the volume of the sample must be known.
The determination of mass can be performed directly using a weighing instrument.
The determination of volume generally cannot be performed directly. Exceptions to this rule
include
· cases where the accuracy is not required to be very high, and
· measurements performed on geometric bodies, such as cubes, cuboids or cylinders, the volume
of which can easily be determined from dimensions such as length, height and diameter.
· The volume of a liquid can be measured in a graduated cylinder or in a pipette; the volume of
solids can be determined by immersing the sample in a cylinder filled with water and then
measuring the rise in the water level.
Because of the difficulty of determining volume with precision, especially when the sample has a
highly irregular shape, a "detour" is often taken when determining the density, by making use of the
Archimedean Principle, which describes the relation between forces (or masses), volumes and
densities of solid samples immersed in liquid:
From everyday experience, everyone is familiar with the effect that an object or body appears to
be lighter than in air – just like your own body in a swimming pool.
Figure 3: The force exerted by a body on a spring scale in air (left) and in water (right)
joules=watts times seconds
600x10 = 6000joules
Answer:
a = 2 m/s²
v₄ = 8 m/s
Explanation:
We can find the final speed at the end of eight second by using first equation of motion:
where,
vf = final velocity at 8th second = 16 m/s
vi = initial velocity = 0 m/s
a = acceleration = ?
t = time = 8 s
Therefore, using the values in the equation we get:
<u>a = 2 m/s²</u>
<u></u>
Now, we can apply same equation of motion for 4 seconds of motion to find the velocity at the end of 4th second (v₄):
<u>v₄ = 8 m/s</u>
Answer:11.101 m/s
Explanation:
Given
Velocity of eagle=3.1 m/s
Eagle is at height of 5.8 m
Fish is dropped with a horizontal velocity of 3.1 m/s
time taken by fish to reach lake is
here u=0 (vertical velocity)
t=1.087 s
Vertical velocity acquired by fish is v=u+at
Horizontal velocity=3.1 m/s
Therefore net velocity
below horizontal
