1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bearhunter [10]
2 years ago
12

Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts

a force of 75.0 N, the second a force of 96.0 N, friction is 12.0 N, and the mass of the third child plus wagon is 27.0 kg.
(a) What is the system of interest if the acceleration of the child in the wagon is to be calculated? (Select all that apply.)
the wagon
the child in the wagon
the children outside the wagon


(b) Draw a free body diagram, including the weight and all other forces acting on the system. (Do this on paper. Your instructor may ask you to turn in this diagram.)
(c) Calculate the acceleration.
m/s2
(d) What would the acceleration be if friction is 21.0 N?
Physics
1 answer:
Nata [24]2 years ago
7 0

(a) The system of interest if the acceleration of the child in the wagon is to be calculated are the wagon and the children outside the wagon.

(b) The acceleration of the child-wagon system is 0.33 m/s².

(c) Acceleration of the child-wagon system is zero when the frictional force is 21 N.

<h3>Net force on the third child</h3>

Apply Newton's second law of motion;

∑F = ma

where;

  • ∑F is net force
  • m is mass of the third child
  • a is acceleration of the third child

∑F = 96 N - 75 N - 12 N = 9 N

Thus, the system of interest if the acceleration of the child in the wagon is to be calculated are;

  • the wagon
  • the children outside the wagon

<h3>Free body diagram</h3>

           →                 →              Ф                         ←

         1st child      friction       wagon                2nd child

<h3>Acceleration of the  child and wagon system</h3>

a = ∑F/m

a = 9 N / 27 kg

a = 0.33 m/s²

<h3>When the frictional force is 21 N</h3>

∑F = 96 N - 75 N - 21 N = 0 N

a = ∑F/m

a = 0/27 kg

a = 0 m/s²

Learn more about net force here: brainly.com/question/14361879

#SPJ1

You might be interested in
A foot player runs 1.6m/s and has a KE of 790 J. What is his mass?
Mariana [72]
The equation for kinetic energy is,

Ke = (1/2)mv^2.

You're given a kinetic energy of 790 joules, and a speed of 1.6 m/s. Plugging these values into the equation, we get,

790 = (1/2)(1.6)^2(m).

Solving for m, we get,

m = (790)/(0.5(1.6)^2).

I'll let you crunch out those numbers for yourself :D

If you have any questions, feel free to ask. Hope this helps!
3 0
3 years ago
How much energy is required to move 2 electrons through a potential difference of 1.0 x 10^ 2 volts?
Ksenya-84 [330]
Charge of electron = 1.6×10−¹⁹

(1.6×10−¹⁹)(1×10²) (2e)

= 3.2×10−¹⁷ J
3 0
3 years ago
Define 1 second time​
malfutka [58]

Answer:

define 1 second time

One second is the time that elapses during 9,192,631,770 (9.192631770 x 10 9 ) cycles of the radiation produced by the transition between two levels of the cesium 133 atom. ... One second is equal to 1/86,400 of a mean solar day.

7 0
3 years ago
Read 2 more answers
If a player through a basketball to the target with an initial velocity of 17 m/s making an angle of 30 degrees with the horizon
Svetllana [295]

Answer:

The final position made with the vertical is 2.77 m.

Explanation:

Given;

initial velocity of the ball, V = 17 m/s

angle of projection, θ = 30⁰

time of motion, t = 1.3 s

The vertical component of the velocity is calculated as;

V_y = Vsin \theta\\\\V_y = 17 \times sin(30)\\\\V_y = 8.5 \ m/s

The final position made with the vertical (Yf) after 1.3 seconds is calculated as;

Y_f = V_yt  - \frac{1}{2}g t^2\\\\Y_f = (8.5 \times 1.3 ) - (\frac{1}{2} \times 9.8 \times 1.3^2)\\\\Y_f = 11.05 \ - \ 8.281\\\\Y_f = 2.77 \ m

Therefore, the final position made with the vertical is 2.77 m.

3 0
3 years ago
1. A change in which one or more substances are converted into new substances is a
Ratling [72]

Answer:

<u>CHEMICAL CHANGE</u>:

A change in which one or more substances are converted into new substances is a  <em>chemical change</em>.

<u>EXPLANATION:</u>

Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.

<u>EXAMPLE:</u>

<em>Examples of Chemical Change in Everyday Life </em>

Burning of paper and log of wood.

Digestion of food.

Boiling an egg.

Chemical battery usage.

Electroplating a metal.

Baking a cake.

Milk going sour.

Various metabolic reactions that take place in the cells.

4 0
3 years ago
Other questions:
  • What is the difference between an iris-in and an iris-out? an iris-in begins with a small circle that expands, while an iris-out
    6·1 answer
  • ___________ is a tiny, hair-like fiber that aids in movement.
    9·1 answer
  • A velocity selector is built with a magnetic field of magnitude 5.2 T and an electric field of strength 4.6 × 10 ^4 N/C. The dir
    15·2 answers
  • A rock that has deformed ____ under stress keeps its new shape when the stress is released.
    13·1 answer
  • What is the best description of a convergent boundary? (Do they move towards eachother, side by side past each other, away from
    9·1 answer
  • A carousel is spinning at a speed of 100 cm/s, with the outermost horse at a distance 5 m from the center.
    6·1 answer
  • 8. An object has a force applied. The object has a mass of 36 Kg and accelerates at 3.4 m/sec2. What is the force acting on the
    10·1 answer
  • How does the mass of and distance between the Sun and the Earth impact the number of days in a year?
    8·1 answer
  • g A high-energy photon turns into and electron and a positron. (A positron has exactly the same mass as the electron, but opposi
    11·1 answer
  • To which end of the horseshoe magnet will the north end of the magnet be attracted
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!