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aev [14]
4 years ago
7

Which scientist was the first to propose the heliocentric model of the universe? A. Aristotle B. Isaac Newton C. Galileo Galilei

D. Nicolaus Copernicus
Physics
2 answers:
Annette [7]4 years ago
6 0

The answer would defiantly be option D "Nicolaus Copernicus." Copernicus was first to purpose the model of the universe, back in 1543 he presented a heliocentric model of the universe, he also made a geocentric model.

Hope this helps!

Nonportrit

ad-work [718]4 years ago
3 0

Answer:

Option (D)

Explanation:

Heliocentric model was discovered by the great scientist <u>Nicolaus Copernicus</u>.

<em>According to the Heliocentrism theory, the sun is believed to be located at the center of our solar system and earth along with other planets revolves around it in a circular path</em>.

There were certain limitation of this theory. This theory was unable to describe why the stars most of the time exist to be at the same place, inspite of the frequently changing positions of earth as it revolves around the sun.

Thus, the correct answer is option (D).

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is described as the sum of all the individual resistances in a series.1) Equivalent resistance2) Parallel circuit3) Series circu
irga5000 [103]

The sum of all resistances in the series circuit is known as Equivalent resistance.

R=r_1+r_2+.\ldots.r_n

where R is the equivalent resistance.

Hence, option 1 is the correct answer.

6 0
1 year ago
A toroidal solenoid has 600 turns, cross-sectional area 6.90 cm2, and mean radius 4.30 cm.
Dahasolnce [82]

(a) The coil's self-inductance is 7.26 mH.

(b) The self-induced emf in the coil is 7.26 V

(c) The direction of the induced emf is from b to a.

<h3>Coil's self-inductance</h3>

L = N²μA/I

L = (600² x 4π x 10⁻⁷ x 6.9 x 10⁻⁴)/(0.043)

L = 7.26 x 10⁻³ H

L = 7.26 mH

<h3>Self-induced emf in the coil</h3>

emf = N(ΔBA)/t

where;

  • B is magnetic field
  • A is area
  • N is number of turns
  • t is time

B = μNI/L

B1 = (4π x 10⁻⁷ x 600 x 5)/0.043

B1 = 0.0876 T

B2 =  (4π x 10⁻⁷ x 600 x 2)/0.043

B2 = 0.035 T

emf = NΔBA/t

emf = (600)(0.0876 - 0.035)(6.9 x 10⁻⁴) / (3 x 10⁻³)

emf = 7.26 V

The direction of the induced emf is always opposite to the direction of the applied current.

Thus, the direction of the induced emf is from b to a.

Learn more about induced emf here: brainly.com/question/13744192

#SPJ1

3 0
2 years ago
Why is the fuse used in a circuit called safety fuse?<br>​
Sunny_sXe [5.5K]

Answer:

The maximum current which can flow through a fuse without melting it, is called its rating. ... If current higher than 8 A flows through the fuse, it would melt and circuit gets broken. ... Hence, fuse acts as a safety device

4 0
3 years ago
Read 2 more answers
HELP ASAP
xeze [42]

Answer:

D) it is neutral

5 0
4 years ago
Read 2 more answers
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