Answer:
Social justice aims to give individuals and groups fair treatment and an impartial share of social, environmental and economic benefits. The concept promotes the fair distribution of advantages and disadvantages within a society, regardless of background and status.
Environmental justice deals explicitly with the distribution of environmental benefits and the burdens people experience, at home, at work, or where they learn, play and spend leisure time. Environmental benefits include attractive and extensive greenspace, clean air and water, and investment in pollution abatement and landscape improvements. Environmental burdens include risks and hazards from industrial, transport-generated and municipal pollution.
Answer:
upward (F=ma if f is up a is up)
B) energy is absorbed by the reaction
is right answer.
Answer:
Le Chatelier's principle can be applied in explaining the results
Explanation:
According to Le Chatelier's principle, when a constraint such as a change in concentration in this case is imposed on a chemical system in equilibrium, the system will adjust itself in such a way as to annul the constraint imposed.
Hence, when the color of the solution was more like that of the control, the reaction would shift towards the left. Similarly, when the color was more like it was towards the reactant, the reaction would shift towards the right.
If we were to prepare calcium oxalate, we should prepare it in a base solution. This is because when the base was added to calcium oxalate, it did not form any precipitate but when an acid was added to the calcium oxalate, it formed a precipitate.
Answer:
Explanation:
We are given that 25 mL of 0.10 M 
is titrated with 0.10 M NaOH(aq).
We have to find the pH of solution
Volume of 
Volume of NaoH=0.01 L
Volume of solution =25 +10=35 mL=
Because 1 L=1000 mL
Molarity of NaOH=Concentration OH-=0.10M
Concentration of H+= Molarity of 
=0.10 M
Number of moles of H+=Molarity multiply by volume of given acid
Number of moles of H+=
=0.0025 moles
Number of moles of 
=0.001mole
Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles
Concentration of H+=
pH=-log [H+]=-log [4.28
]=-log4.28+2 log 10=-0.631+2
