Answer:
6.7970 g
Explanation:
Considering the Henderson- Hasselbalch equation for the calculation of the pOH of the basic buffer solution as:
pOH = pK + log[acid] / [base]
Where K is the dissociation constant of the base.
Base dissociation constant of the ammonia = 1.8×10⁻⁵
pK = - log (Kb) = - log (1.8×10⁻⁵) = 4.75
Given concentration of base = [base] = 0.273 M
pH = 10.150
pOH = 14 - pH = 14 - 10.150 = 3.85
So,
3.85 = 4.75 + log[acid]/0.273
[Acid] = 0.0347 M
Given that Volume = 2 L
So, Moles = Molarity × Volume
Moles = 0.0347 × 2 = 0.0694 moles
Molar mass of ammonium bromide = 97.94 g/mol
Mass = Moles × Molar mass = (0.00775 × 97.94) g = 6.7970 g
Answer:
sunlight is the answer i think
Do 36-29 which is 7 and since 29 is before 36 it’s negative so -7
Density is calculated as mass divided by volume. We are given the mass of 15.0 grams, so we need to find the volume. For a cube, volume is calculated as (length of side)^3, so in this case, we have the length of a side as 44.5 mm, which is equivalent to 4.45 cm.
Volume = (4.45 cm)^3 = 88.1 cm^3
Then we divide mass by the volume:
Density = (15.0 grams) / (88.1 cm^3) = 0.170 g/cm^3
So the correct answer is A.