Given the following equation: K+Cl2>KCl balance the equation

PLEASE HELP ASAP!!!

gavmur [86]

Answer:

A

Explanation:

5 0

2 years ago

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How many neutrons are present in 1 atom of chlorine?

pav-90 [236]

The answer is A.18 let me know if you want an explanation

4 0

2 years ago

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Your task is to create a buffered solution. You are provided with 0.10 M solutions of formic acid and sodium formate. Formic aci

Anton [14]

Answer:

15.2mL of the 0.10M sodium formate solution and 4.8mL of the 0.10M formic acid solution.

Explanation:

To find the pH of a buffer based on the concentration of the acid and conjugate base we must use Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where [A⁻] could be taken as moles of the sodium formate and [HA] moles of the formic acid</em>

<em />

4.25 = 3.75 + log [A⁻] / [HA]

0.5 = log [A⁻] / [HA]

3.162 = [A⁻] / [HA] <em>(1)</em>

As both solutions are 0.10M and you want to create 20mL of the buffer, the moles are:

0.10M * 20x10⁻³L =

2x10⁻³moles = [A⁻] + [HA] <em>(2)</em>

Replacing (2) in (1):

3.162 = 2x10⁻³moles - [HA] / [HA]

3.162 [HA] = 2x10⁻³moles - [HA]

4.162[HA] = 2x10⁻³moles

[HA] = 4.805x10⁻⁴ moles

[A⁻] = 2x10⁻³moles - 4.805x10⁻⁴ moles = 1.5195x10⁻³moles

That means, to create the buffer you must add:

[A⁻] = 1.5195x10⁻³moles * (1L / 0.10mol) = 0.0152L =

<h3>15.2mL of the 0.10M sodium formate solution</h3>

[HA] = 4.805x10⁻⁴ moles * (1L / 0.10mol) = 0.0048L =

<h3>4.8mL of the 0.10M formic acid solution</h3>

4 0

2 years ago

Which compound contains a triple bond?

Igoryamba

There are many compounds which contain triple bonds between two atoms. Few of the are as follow,

Nitrogen Molecule:

   N₂ or :N≡N:

Cyanide Ion:

  CN⁻ or [:C≡N:]⁻

Alkynes:
   R-C≡C-R

Carbon Monoxide:

CO or :C≡O:

Among given compounds Alkynes belong to a class of unsaturated hydrocarbons. The carbon atom in alkyne is sp hybridized. These unsaturated hydrocarbons have their own characteristic chemical properties.

6 0

2 years ago

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Two perfumes are released at the same time. If one is standing 7.5 m from the point of release. Perfume A (molar mass 275 g/mol)

natta225 [31]

According to Graham's Law of Diffusion," Diffusion of Gas is inversely proportional to square root of its Molecular Mass or Density".

rᵇ/rᵃ =   $\sqrt{da/db}$
Or,
  rᵇ/rᵃ =   $\sqrt{Ma/Mb}$ ----- (1)
As,
Ma = 275 g/mol

Mb = 205 g/mol

Putting Values in eq.1,

rᵇ/rᵃ =   $\sqrt{275/205}$

rᵇ/rᵃ = 1.15

Result:
Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.

6 0

2 years ago