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Licemer1 [7]
3 years ago
5

Given the following equation: K+Cl2>KCl balance the equation

Chemistry
1 answer:
Sonja [21]3 years ago
8 0
Balanced equation : 2K + Cl2 > 2KCL.
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As the volume of a gas increases, what happens to the pressure of the gas?
Elena L [17]
Boyle found that when the pressure of gas at a constant temperature is increased, the volume of the gas decreases. when the pressure of gas is decreased, the volume increases. this relationship between pressure and volume is called Boyle's law.
4 0
2 years ago
(First to answer gets some good) Order the following components of the universe from largest to smallest: Moon, planet,universe,
cluponka [151]

Answer:

Universe, galaxy, solar system, star, planet, moon and asteroid.

Explanation:

You're welcome!

7 0
3 years ago
If you are given a 0. 31 g piece of sodium metal to react with water, how many moles of hcl would it take to neutralize the sodi
Sphinxa [80]

The moles of HCl to neutralize the sodium hydroxide produced is<u> 0.0135 mole.  </u>

Neutralization or neutralization is a chemical response wherein an acid and a base react quantitatively with each other. In a reaction in water, neutralization outcomes in there being no excess of hydrogen or hydroxide ions gift in the answer.

<u>calculation:-</u>

<u />

2Na + 2H₂O  -----> 2NaOH + H₂

2 mol or 46g of Na produces 80 grams of NaOH

∴ 0.31 g of Na will produce = 80/46 × 0.31

                                              =  0.54 gram of NaOH.

mol of NaOH = 0.54/40

                      = 0.0135

Since both Hcl and NaOH have the same valance factor,

1 mole NaOH is needed to neutralize 1 mol HCl

∴ 0.0135 mole of NaOH will need = 0.0135 mole of HCl

mass = 0.0135 × 36.5

         =<u> 0.493 grams of HCL.</u>

Learn more about neutralizing here:-brainly.com/question/23008798

#SPJ4

4 0
1 year ago
Acetic acid, CH3COOH, can be produced by bubbling oxygen gas into acetaldehyde, CH3CHO, in the presence of
slamgirl [31]

Explanation:

The balanced equation for the reaction is given as;

2CH3CHO + O2 → 2CH3COOH  

If 20.0 g CH3CHO and 10.0 g O2 were put into a reaction vessel, (a)

how many grams of acetic acid will be produced?

First thing's first, we have to find he limiting reactant. This is done by comparing the number of moles of the reactants.

From the equation of the reaction;

2 mol of CH3CHO reacts with 1 mol of O2

From the masses given;

Number of moles = Mass / Molar mass

CH3CHO;

Number of moles = 20 / 44.0526 = 0.454 mol

O2;

Number of moles = 10 / 32 = 0.3125 mol

The limiting reactant is CH3CHO because O2 would be in excess.

Back to the question;

2 mol of CH3CHO produces 2 mol of CH3COOH  

0.454 mol would produce x

Solving for x;

x = 0.454 * 2 / 2 = 0.454 mol

Converting to mass;

Mass = number of moles* Molar mass

Mass = 0.454 mol *  60.052 g/mol = 27.26 grams

(b) how many grams of the excess reactant remain after the reaction is

complete

The excess reactant is O2

Number of moles left = Initial Number of moles - Number of moles that reacted

Number of moles left =  0.3125 mol - (0.454 mol / 2)

Number of moles left = 0.0855 mol

Converting to mass;

Mass = 0.0855 mol * 32 g/mol = 2.736 grams

6 0
3 years ago
Which statement accurately describes a light-year?(Select One) It is the shape of a galaxy. It is the distance that light travel
Strike441 [17]

Answer: B

Explanation:

3 0
3 years ago
Read 2 more answers
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