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Yuliya22 [10]
3 years ago
14

What is the range for 6 12 5 7 7 3 9

Mathematics
2 answers:
AysviL [449]3 years ago
7 0

Answer:

12-3

9 is the range

hope this helps

have a good day :)

Step-by-step explanation:

Andrews [41]3 years ago
5 0

Answer:

9

Step-by-step explanation:

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461÷301 give the answer​
Oksanka [162]

1.53156146179 that is the answer

8 0
3 years ago
A rescue helicopter is used to help victims who fell in a ditch. The helicopter begins at sea level, which is an elevation of 0
Otrada [13]

Answer:

The helicopter still needs to fly up sec 17.0886 at maximum speed.

Step-by-step explanation:


8 0
3 years ago
The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon
Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

The population we estimated in 12.5 million people with a total of driven miles per year of about  

12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

\bf P(t)= Ce^{kt}

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

\bf P(t)= 10.3e^{kt}

Given that P(10)=12.5

\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936

And the function that models the population growth is

\bf P(t)= 10.3e^{0.01936t}

We need P(20)

\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

6 0
3 years ago
Help ASAP worth 20 points please help me
Savatey [412]

Answer:

What do you mean by a tap diagram?

Step-by-step explanation:

4 0
3 years ago
Solve for a.<br><br> a+(−1.2)=−5.5
Oksanka [162]
It is a + (-1.2) = -5.5
= a - 1.2 = -5.5
= a = -5.5 + 1.2
= a = -4.3

In short, Your Answer would be -4.3

Hope this helps!
4 0
3 years ago
Read 2 more answers
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