1.5+(-8.3)
=1.5-8.3
-6.8
The answer is -6.8
Given the expression,

We will have to rationalize the denominator first. To rationalize the denominator we have to multiply the numerator and denominator both by the square root part of the denominator.
![[(8x-56x^2)(\sqrt{14x-2})]/[(\sqrt{14x-2})(\sqrt{14x-2})]](https://tex.z-dn.net/?f=%20%5B%288x-56x%5E2%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%5B%28%5Csqrt%7B14x-2%7D%29%28%5Csqrt%7B14x-2%7D%29%5D%20)
If we have
, we will get
by multiplying them. And
.
So here in the problem, we will get,
![[(8x-56x^2)(\sqrt{14x-2})]/(14x-2)](https://tex.z-dn.net/?f=%20%5B%288x-56x%5E2%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%2814x-2%29%20)
Now in the numerator we have
. We can check 8x is common there. we will take out -8x from it, we will get,


And in the denominator we have
. We can check 2 is common there. If we take out 2 from it we will get,

So we can write the expression as
![[(-8x)(7x-1)(\sqrt{14x-2})]/[2(7x-1)]](https://tex.z-dn.net/?f=%20%5B%28-8x%29%287x-1%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%5B2%287x-1%29%5D%20)
is common to the numerator and denominator both, if we cancel it we will get,

We can divide -8 by the denominator, as -8 os divisible by 2. By dividing them we will get,


So we have got the required answer here.
The correct option is the last one.
There are 2 cows and 1 chicken how many animals are there?
3 animals
Answer:
For maximum area, all of the wire should be used to construct the square.
The minimum total area is obtained when length of the wire is 10m
Step-by-step explanation:
For maximum, we use the whole length
For minimum,
supposed the x length was used for the square,
the length of the side of the square = x/4m
Area =
For the equilateral triangle, the length of the side = 
Area = 
Total Area =
+ 

, therefore it is minimum


x = 10.00m