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Bogdan [553]
3 years ago
15

The four major functions of harmony are

Biology
1 answer:
Fantom [35]3 years ago
6 0

hi,

your answer to the respone is

chord, progression, consonance, dissonance,

i hope this helps have a great evening and can you please MArk  as brainlest ?

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Where to rescue workers get their energy
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The rescue workers can get energy to the batteries in their equipment during rescue missions by using a generator to convert the kinetic energy to potential energy. Potential energy is then stored in the battery.
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3 years ago
What structural feature in a molecule is necessary for a gas to absorb ir radiation?.
dybincka [34]

The structural feature in a molecule necessary for a gas to absorb IR radiation is: a net change in dipole moment due to the vibration or rotation of the molecule.

IR radiation is the infrared radiation. In the electromagnetic spectrum, its value ranges from  700 nanometers to 1 millimeter. The waves are longer than that of visible light and shorter than the radio waves. The waves are not visible to the human eye.

Dipole moment is a vector quantity. It is equal to the charge of the molecules multiplied by the distance between the two charges. In a dipole there is a positive charge at one end and a negative at the other. The direction is considered from negative to positive.

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7 0
1 year ago
Calculate the final concentration of BSA in the problems below using the formula
Rudiy27

Answer:

A. C_2=1.5\frac{mg}{mL}

B. C_2=0.075\frac{mg}{mL}

C. C_2=0.01\frac{mg}{mL}

D. C_2=0.001\frac{mg}{mL}

Explanation:

Hello.

In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:

C_2=\frac{C_1V_1}{V_2}

Thus, we proceed as follows:

A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.

C_2=\frac{300\mu L*5\frac{mg}{mL} }{(300+700)\mu L}\\\\C_2=1.5\frac{mg}{mL}

B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.

C_2=\frac{50\mu L*1.5\frac{mg}{mL} }{(50+450+500)\mu L}\\\\C_2=0.075\frac{mg}{mL}

C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.01\frac{mg}{mL}

D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.

C_2=\frac{10\mu L*0.1\frac{mg}{mL} }{(10+990)\mu L}\\\\C_2=0.001\frac{mg}{mL}

Best regards.

7 0
3 years ago
Excretion is the process of removing wastes and excess water from the body.<br><br> True <br> false
JulijaS [17]
True. feces, also known as excrement are the product of excretion.
3 0
3 years ago
Which could be a primary source of energy in a food web?
Deffense [45]

Answer:

The plant which I think it says clover i can see

Explanation:

plants are primary sources of energy because it makes it own food and doesn't take form other animals.

6 0
2 years ago
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