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Paha777 [63]
3 years ago
11

It all adds up worksheet

Chemistry
1 answer:
Komok [63]3 years ago
8 0
Atomic number and the number of protons are the same...
Neutrons = Mass number - number of protons
Electrons are same # unless there is a charge 
The whole number you see on the periodic table is the atomic number of the element which is also same as the number of protons

1) carbon - 14  ;  Mass number = 14 , Protons = 6 , Neutrons = 14 - 6 = 8 
                                Electrons = 6 

2) Lead - 208  ; Mass # = 208 , Protons = 82 , Neutrons = 208 - 82 = 126
                          Electrons = 82

3) Uranium - 239 ; Mass # = 239  , Protons  =  92,Neutrons = 239 - 92 = 147
                                 Electrons =  92

4) Uranium - 238  ; Mass # = 238 , Protons = 92 , Neutrons = 238 - 92 = 146
                                   
Electrons = 92 

5) Tin - 118  ; Mass # = 118 , Protons = 50 , Neutrons = 118 - 50 = 68
                         Electrons = 50
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One mole of an ideal gas, for which CV,m = 3/2R, initially at 298 K and 1.00 × 105 Pa undergoes a reversible adiabatic compressi
oksian1 [2.3K]

Answer:

  • final temperature (T2) = 748.66 K
  • ΔU = w = 5620.26 J
  • ΔH = 9367.047 J
  • q = 0

Explanation:

ideal gas:

  • PV = RTn

reversible adiabatic compression:

  • δU = δq + δw = CvδT

∴ q = 0

∴ w = - PδV

⇒ δU = δw

⇒ CvδT = - PδV

ideal gas:

⇒ PδV + VδP = RδT

⇒ PδV = RδT - VδP = - CvδT

⇒ RδT - RTn/PδP = - CvδT

⇒ (R + Cv,m)∫δT/T = R∫δP/P

⇒ [(R + Cv,m)/R] Ln (T2/T1) = Ln (P2/P1) = Ln (1 E6/1 E5) = 2.303

∴ (R + Cv,m)/R = (R + (3/2)R)/R = 5/2R/R = 2.5

⇒ Ln(T2/T1) = 2.303 / 2.5 = 0.9212

⇒ T2/T1 = 2.512

∴ T1 = 298 K

⇒ T2 = (298 K)×(2.512)

⇒ T2 = 748.66 K

⇒ ΔU = Cv,mΔT

⇒ ΔU = (3/2)R(748.66 - 298)

∴ R = 8.314 J/K.mol

⇒ ΔU = 5620.26 J

⇒ w = 5620.26 J

  • H = U + nRT

⇒ ΔH = ΔU + nRΔT

⇒ ΔH = 5620.26 J + (1 mol)(8.314 J/K.mol)(450.66 K)

⇒ ΔH = 5620.26 J + 3746.787 J

⇒ ΔH = 9367.047 J

8 0
3 years ago
How many watts of power (W) do you expend when you exert a force of 10 N that moves a
mihalych1998 [28]

Answer:

Power = 7.5 watt

Explanation:

Given data:

Power expend = ?

Force applied = 10 N

Distance cover = 1.5 m

Time = 2 s

Solution:

Power = work/ time

First of all we will calculate work.

Work = Force × distance

Work = 10 N × 1.5 m

Work = 15 N.m

Now we will calculate the power.

Power = 15 N.m / 2s

N.m/s = 1 watt

Power = 7.5 watt

7 0
3 years ago
The very common mineral shown in this photograph is commonly a pink- to cream-colored mineral with wavy, light-colored lines. it
musickatia [10]
The very common mineral shown in the figure that is referred in this problem that is commonly a pink- to cream-colored mineral with wavy, light-colored lines and does not effervesce would be feldspar. It make up about 41 percent weight of the Earth's crust. It is a group of rocks that contains tectosilicate compounds.
8 0
3 years ago
The___ step in balancing a chemical equation is to take inventory or count atoms on the reactant & the product side.
Kazeer [188]

Answer: The first step in balancing a chemical equation is to take inventory or count atoms on the reactant & the product side.

Explanation:

***If you found my answer helpful, please give me the brainliest. :) ***

6 0
3 years ago
What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.3×1015Hz?
Sonja [21]

Answer:

We know that

ħf = ф + Ekmax  

where  

ħ = planks constant = 6.626x10^-34 J s  

f = frequency of incident light = 1.3x10^15 /s (1 Hz =

1/s)

ф = work function of the cesium = 2.14 eV  

Ekmax = max  kinetic energy of the emmitted electron.  

We distinguish that:

1 eV = 1.602x10^-19 J

So:

2.14 eV x (1.602x10^-19 J / 1 eV) = 3.428x10^-19 J

So,

Ekmax = (6.626x10^-34 J s) x (1.3x10^15 / s) - 3.428x10^-19 J

= 8.6138x10^-19 J - 3.428x10^-19 J = 5.1858x10^-19 J  

Answer:

5.19x10^-19 J  

Kinetic energy:

In physics, the kinetic energy of an object is the energy that it owns due to its motion. It is defined as the work required accelerating a body of a given mass from rest to its specified velocity. Having expanded this energy during its acceleration, the body upholds this kinetic energy lest its speed changes.

Answer details:

Subject: Chemistry

Level: College

Keywords:

• Energy  

• Kinetic energy

• Kinetic energy of emitted electrons

Learn more to evaluate:

brainly.com/question/4997492

brainly.com/question/4010464

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6 0
3 years ago
Read 2 more answers
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