The electrical wires in your home use what type of circuits?

2 answers:

8 0

Parallel circuits) Parallel circuts have two or more paths which would be better for a home, the amount of voltage is the same on each side making it safer to live.

Helga [31]3 years ago

7 0

The house wiring should be done parallel because, in parallel connection there will be more advantages than a series connection.

Let a house is wired in series and it contains a fan, tube light, TV, refrigerator. All the devices are connected in series. Now, due to some disturbance the fan speed working or it burned. Then since the connection was a series, due to one appliance failure causes the whole circuit to fail. If it is burned that means it making an open circiut. Then there will be no current flow in the circuit.

Now if it was a parallel connection as we know already, the parallel connection is nothing but individual appliances connected to the same line by tappings. That means there's no dependency of one appliance on another. So if an appliance fail or burns it doesn't effects the remaining appliances. And there will be uninterrupted supply to the healthy appliances can be achieved.

That’s why we use parallel for house wiring

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Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = $1.83g/cm^3=1.83g/ml$

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

$\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml$

Now we have to calculate the molarity of solution.

$Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L$

Now we have to calculate the molality of the solution.

$Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg$