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balandron [24]
3 years ago
8

If 143.56 mL of 0.6653 M ammonium carbonate reacts with 175.37 mL of 0.8732 M chromium(III) sulfate in a double replacement reac

tion and produces 7.543 g of chromium(III) carbonate, what is the percent yield of the reaction
Chemistry
2 answers:
SSSSS [86.1K]3 years ago
8 0
I think it’s 7543 g of chromium
Cloud [144]3 years ago
4 0
ANSWER=83.42%

EXPLANATION:

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The answer is A
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The vapor pressure of dichloromethane, c h 2 c l 2 , at 0 ∘ c is 134 mmhg . the normal boiling point of dichloromethane is 40. ∘
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8 0
4 years ago
Luke and Sian want to plant a vegetable garden in their yard. A soil testing kit measures the soil pH at 5.0, but the lettuce th
dexar [7]

Answer:

So, Luke and Sian has to increase the pH of the soil by adding base to it.

Explanation:

The pH is defined as the negative logarithm of the hydrogen ion concentration in their aqueous solution.

pH=-\log[H^+]

  • With increase in hydrogen ion concentration the pH value decreases.
  • With decrease in hydrogen ion concentration the pH value increases.

The pH of the soil after testing it on a kit comes out be 5.0, but they both need pH of the soil to 6.5.

Comparison of pH of soil:

  =  5.0 < 6.5

= High hydrogen ion concentration > High hydrogen ion concentration

So, Luke and Sian has to increase the pH of the soil by adding base .Doing so will decrease the hydrogen ion concentration in the soil (where as addition of acid lower the pH of soil).

4 0
3 years ago
What is list of solutions
VashaNatasha [74]
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3 0
4 years ago
Arterial blood contains about 0.25 g of oxygen per liter at 37°C and standard atmospheric pressure. Under these conditions, the
Olin [163]

Firstly we need to determine the partial pressure of O2:

\begin{gathered} P_{O_2}=X\times P_T \\ P_{O_2}:partial\text{ }pressure \\ X:mole\text{ }fraction \\ P_T:total\text{ }pressure \\  \\ P_{O_2}=0.209\times0.35\text{ }atm \\ P_{O_2}=0.073\text{ }atm \end{gathered}

We will now use the Henry's Law equation to determine the solubility of the gas:

\begin{gathered} c=K_H\times P_{O_2} \\ c:solubility\text{ }or\text{ }concentration\text{ }of\text{ }the\text{ }gas(M) \\ K_H:Henry^{\prime}sLawconstant=3.7\times10^{-2}M\text{ }atm^{-1} \\ P_{O_2}:partial\text{ }pressure\text{ }of\text{ }the\text{ }gas=0.073atm \\  \\ c=3.7\times10^{-2}M\text{ }atm^{-1}\times0.073 \\ c=2.7\times10^{-3}M \end{gathered}

Answer: Solubility is 2.7x10^-3 M

6 0
1 year ago
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