This question provides us –
- Weight of
is = 47 g - Volume, V = 375 mL
__________________________________________
- Molar Mass of
–
<u>Using formula</u> –
- Henceforth, Molarity of the solution is = 1.7M
___________________________________________
Data Given:
Pressure = P = ?
Volume = V = 3.0 L
Temperature = T = 115 °C + 273 = 388 K
Mass = m = 75.0 g
M.mass = M = 44 g/mol
Solution:
Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
P V = n R T
Solving for P,
P = n R T / V ------ (1)
Calculating Moles,
n = m / M
n = 75.0 g / 44 g.mol⁻¹
n = 1.704 mol
Putting Values in Eq. 1,
P = (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L
P = 18.08 atm
Tearing paper, Physical Change
15% = 15 grams of solute in 100 mL solution
15 g --------------- 100 mL
?? ------------------ 1000 mL
1000 x 15 / 100 =
15000 / 100 => 150 g of solute
hope this helps!
