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Alja [10]
3 years ago
6

You find an unknown substance, which has a density of 10.0 g/ml, and occupies a volume of 80.0 ml. What is the mass of the unkno

wn?
Chemistry
1 answer:
Svetlanka [38]3 years ago
4 0

Answer:

Density=mass / volume.

10= mass /80.

mass=10×80.

=800g

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BALANCE the following equations then write the NET IONIC EQUATION for each one: ____Ni(NO​ 3​ )​ 2​​(aq)​ + ____NaOH ​(aq)​ ​→ ​
Karo-lina-s [1.5K]

Answer:

Ni(NO3)2 + 2NaOH → Ni(OH)2 + 2NaNO3

NET IONIC EQUATION :

Ni +2(aq)  + 2(NO3) -1(aq)  + 2Na +1(aq)  + 2OH -1(aq)

→ Ni(OH)2 (s)  + 2Na +1(aq)  +  2(NO3) -1(aq)

sorry there is no space to write the reaction in one line...

8 0
3 years ago
Al2(SO4)3+Mg(NO3)2⟶ What would be the product(s) of this reaction? *These are NOT balanced, just look for the correct products*
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Answer:

Al_2(SO_4)_3+3Mg(NO_3)_2\rightarrow 2Al(NO_3)_3+3MgSO_4

Explanation:

Hello there!

In this case, for the given reactants side, we infer this is a double replacement reaction because all the cations and anions are switched around as a result of the chemical change, we infer that the products side include aluminum with nitrate and magnesium with sulfate as shown below:

Al_2(SO_4)_3+Mg(NO_3)_2\rightarrow Al(NO_3)_3+MgSO_4

However, we need to balance since unequal number of atoms are present at both sides, thus, we do that as shown below:

Al_2(SO_4)_3+3Mg(NO_3)_2\rightarrow 2Al(NO_3)_3+3MgSO_4

Thus, we make 6 Al atoms, 3 S atoms, 3 Mg atoms and 30 O atoms on each side in agreement with the law of conservation of mass.

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7 0
2 years ago
How many atoms of oxygen (o)are present 2naOH+H2SO4 2H2O+Na2SO4
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Answer:

10

Explanation:

6 0
3 years ago
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2 years ago
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weqwewe [10]

Answer:

3.91 L

Explanation:

Using the ideal gas law equation as follows:

PV = nRT

Where:

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

Based on the information given in this question,

P = 5.23 atm

V= ?

n = 0.831 mol

T = 27°C = 27 + 273 = 300K

Using PV = nRT

V = nRT/P

V = (0.831 × 0.0821 × 300) ÷ 5.23

V = 20.47 ÷ 5.23

V = 3.91 L

8 0
3 years ago
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