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Anna71 [15]
2 years ago
9

Question 17 of 25

Chemistry
2 answers:
lesya [120]2 years ago
5 0

Answer: it is Cu(s)

Explanation:

OLga [1]2 years ago
3 0
The answer is B Ni(s)

nickel atom will oxidised to become nickel ion, Ni2+
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Suppose a student did not fully redissolve the Al(OH)3 that initially formed upon the addition of H2SO4. Predict and explain how
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Sulphur burnt in oxygen forms sulphur dioxide. Calculate the heat given out when 1.6g of sulphur is burnt.
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Methane from ohio's rose valley coal mine has successfully been used to power fuel cells. since the fuel used in these cells is
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2 years ago
What is the value of the rate constant k for this reaction?When entering compound units, indicate multiplication of units explic
vekshin1

The table with the data is in the picture attached.

Answer:

  • k=0.0033M^{-2}.s^{-1}

Explanation:

The reaction equation suggests that the law could have this form:

  • rate=k[A]^a[B]^b[C]^c

Then, the work is to find the values of the exponents that satisfy the initial rate data.

A first glance shows that for the third and fourth trials the initial rates are the same. Since for these two trials only the initial concentration of substance B changed (A and C were kept equal), you conclude that the reaction rate does not depend on B, and ist exponent (lower b) is 0.

Then, so far you can say:

  • rate=k[A]^a[C]^c

When you use trials 1 and 2, you get:

\frac{r_2}{r_1}=\frac{27M/s}{9M/s}=\frac{(0.3M)^a(0.3M)^b(0.9M)^c}{(0.3M)^a(0.3M)^b(0.3M)^c}=3^c\\\\ 3=3^c\\ \\ 1=c

Now, you can use trials 1 and 3 to determine the other exponent:

\frac{r_3}{r_1}=\frac{36M/s}{9M/s}=\frac{(0.6M)^a(0.3M)^b(0.3M)^c}{(0.3M)^a(0.3M)^b(0.3M)^c}=2^a\\\\ 4=2^a\\ \\ 2^2=2^a\\ \\ 2=a

Thus, you have the rate law:

  • r=k[A]^2[C]

Now, you just use any trial to obtain k. Using trail 1:

  • k(0.3M)^2(0.3M)=9.10^{-5}M/s

Which yields:

  • k=0.0033M^{-2}.s^{-1}

4 0
3 years ago
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