1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
garri49 [273]
2 years ago
9

What is the first stage of speciation

Chemistry
2 answers:
jonny [76]2 years ago
5 0
The first stage is usually when a population become separated from the rest of their species.
tia_tia [17]2 years ago
5 0
The first stage of speciation is separation.So the answer would be the populations become totally separate from one another.
You might be interested in
By making several measurements with the same balance, a chemist obtained values of 5.224 g, 5.235 g, and 5.259 g for the mass of
stepan [7]

Answer:

a) Measurements have a good precision.

Explanation:

Accuracy is the proximity of the data to the value considered as real, in this situation we do not know the real value and we do not know if the data is accurate or not, so we can discard options b and d.

Now, precision is the proximity of the data obtained among themselves and that is what we can observe, so the appropriate answer is the option a.

6 0
3 years ago
Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3). us
BartSMP [9]

Answer:

0.85 mole

Explanation:

Step 1:

The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:

When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:

CaCl2 + Na2CO3 -> CaCO3 + 2NaCl

Step 2:

Conversion of 85g of CaCO3 to mole. This is illustrated below:

Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

Mass of CaCO3 = 85g

Moles of CaCO3 =?

Number of mole = Mass /Molar Mass

Mole of CaCO3 = 85/100

Mole of caco= 0.85 mole

Step 3:

Determination of the number of mole of CaCl2 needed to produce 85g (i.e 0. 85 mole) of CaCO3.

This is illustrated below :

From the balanced equation above,

1 mole of CaCl2 reacted to produced 1 mole of CaCO3.

Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.

From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3

5 0
3 years ago
Read 2 more answers
I AM GETTING TIMED! PLEASE HELP ME!!
Elena L [17]

Explanation:

no.A (He) I think.............

5 0
2 years ago
If a substance changes color, what has most likely happened
BabaBlast [244]

say for example, the color of our blood inside the body is blue, when you have a cut, th he blood color is red through oxygenation.

5 0
2 years ago
Identify the compound that has the same structure as sodium chloride. identify the compound that has the same structure as sodiu
olga_2 [115]
Sodium chloride is an ionic compound. ionic compound is when the compound itself is made up of a metal and non-metal element.
thus the answer is potassium bromide and cesium chloride.
8 0
3 years ago
Read 2 more answers
Other questions:
  • how do the differences in the polyatomic ions po3^3- and po4^3- help you determine whether each ends in -ite or -ate
    10·2 answers
  • what is the difference between aqueous hydrogen fluoride and hydrofluoric acid? do they have different formulas or are they just
    6·1 answer
  • A solution has the same or different properties to the solute and solvent making it up
    9·1 answer
  • The formation of a plaque and halitosis can be avoided by brushing and flossing at least :
    15·1 answer
  • Identify the strongest attractive forces between the particles of each of the following A.CH3OH B.CO C.CF4 D.CH3-CH3
    9·2 answers
  • Write iupac name of :
    7·1 answer
  • ¿Qué forma tiene la máquina simple llamada cuña?
    12·1 answer
  • 26. A Grignard's reagent may be made by
    9·1 answer
  • What happens to valence electrons when a covalent bond forms?
    6·1 answer
  • GIVING BRAILIEST FOR ANSWER
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!