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3 years ago

What is the slope of a line that goes through the points (4,1) and (2,5)

1 answer:

5 0

$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - 1}{2 - 4} = \frac{4}{-2} = -2$

$y - y_1 = m(x - x_1)$
$y - 1 = -2(x - 4)$
$y - 1 = -2x + 8$
 $y = -2x + 9$

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Using the distributive property simplify the expression -3(x - 2) + 4

S_A_V [24]

Answer:

-3x+10

Step-by-step explanation:

-3(x - 2) + 4

Using the distributive property:

-3*x-3*(-2)+4

we have:

-3x+6+4

-3x+10

8 0

3 years ago

Read 2 more answers

I need help :,)

Dmitry_Shevchenko [17]

Answer:

add 17.50 to 8.75 you get 26.25

7 0

2 years ago

Read 2 more answers

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ cross multiply

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

3 years ago

Which description best compares the graphs given by the equations:

nexus9112 [7]

x - 5y = -5, -5x - 25y = 25

First, you'll need to get the x variable by itself.

x - 5y = -5
 +5 +5
 x = 0
So x is plotted on the 0.

For the second part of the first equation, you'll be looking for what the y variable represents.

x - 5y = -5
-x -x
 -5y = -5
 5 5
 y = 1
So y is plotted on the 1 on the vertical line above the 0.

For the first part of the second equation, you'll do the same thing as in the first equation.

-5x - 25y = 25
 +25 +25
 -5x = 50
 5 5
x = 10
So the x for this equation is plotted on 10 on the horizontal line.

For the second part of the second equation, you will do the same thing as in the first equation.

-5x - 25y = 25
+5 +5
 -25y = 30
 25 25
y = 1.2
So the y for the second half of the second question is plotted on 1.2 on the vertical line.