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RSB [31]
3 years ago
9

When jumping, a flea accelerates at an astounding 1300 m/s2 , but over only the very short distance of 0.51 mm ?

Physics
1 answer:
Flauer [41]3 years ago
5 0

the complete question in the attached figure

we have that 

d=0.51 mm------------------------- >0.00051 m 

v = √(2ad) = √(2 * 1300m/s² * 0.00051 m) = 1.15 m/s initial velocity 

a=9.8 m/s²

Then d = v² / 2a = (1.15m/s)² / (2*9.8) m/s² = 0.059 m = 59 mm

the answer is 59 mm

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Answer:

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(b). The direction of the first ball after the collision is 44.16° due south of east.

Explanation:

Given that,

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m = m_{1}=m_{2}

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m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

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m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}

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v_{1}=-v_{2}

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(b) We need to calculate the direction of the first ball after the collision

Using formula of direction

\tan\theta=\dfrac{v_{2}}{v_{1}}

\tan\theta=\dfrac{-1.36}{1.4}

\theta=\tan^{-1}\dfrac{-1.36}{1.4}

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7 0
3 years ago
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Answer:

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=>   E  A  =  \frac{q}{\epsilon_o }

Given that  the electric field is pointing downward  , the equation become

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