Answer:
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Explanation:
The time taken for the train to stop is 8.9 seconds.
The distance traveled by the train during acceleration is 9,984 m.
The distance traveled by the train during deceleration is 17.8 m.
<h3>
Time taken for the train to stop</h3>
Use the following kinematic equation to determine the time taken for the train to stop.
v = u + at
where;
- v is the final velocity of the train = 0
- u is the initial velocity = 4 m/s
- a is the deceleration = -0.45 m/s²
- t is time of motion
0 = 4 - 0.45t
0.45t = 4
t = 4/0.45
t = 8.89 seconds = 8.9 seconds
<h3>Distance traveled by the train during acceleration</h3>
s = ut + ¹/₂at²
where;
- t is time of motion = 8 min = 480 seconds
s = (4)(480) + ¹/₂(0.07)(480)²
s = 9,984 m
<h3>Distance traveled by the train during deceleration</h3>
s = ut + ¹/₂at²
s = (4 x 8.9) + ¹/₂(-0.45)(8.9)²
s = (4 x 8.9) - ¹/₂(0.45)(8.9)²
s = 17.8 m
Learn more about deceleration here: brainly.com/question/75351
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Answer:
This question can only be answered by you.
Explanation:
This question must be tailored specificly to you. whatever your next class is you must write 8 sentences on your walk to it. You can try going into detail about who you saw on the walk. where you went.what people were doing in the hallway. Did you look out a window? what did you see? how long did it take you to walk there? do you usually stop at your locker?
Also dont forget to use a colon ( : ): This can be used when listing things
semicolon (;) : is used as a pause (Seperation) in a long sentence.
Try incorperating some of the five senses in your sentences.
Good luck!