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Dmitry_Shevchenko [17]
2 years ago
15

Which force is represented by the arrow at A?

Physics
2 answers:
Nat2105 [25]2 years ago
7 0

Answer:

B) Force of gravity

Explanation:

As it is the force which acts downward on the body towards the ground, it is clearly the force gravity represented by the arrow at A.

Tom [10]2 years ago
4 0

Which force is represented by the arrow at A?

  • <em>B) Force of gravity</em>

<u>Let us understand the situation first and then we will understand which type of force is represented by arrow A </u>

  • <em>The</em><em> </em><em>line</em><em> </em><em>to</em><em> </em><em>which</em><em> </em><em>arrow</em><em> </em><em>A</em><em> </em><em>is</em><em> </em><em>being</em><em> </em><em>touched</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>ground</em><em> </em><em>and</em><em> </em><em>the</em><em> </em><em>block</em><em> </em><em>is</em><em> </em><em>being</em><em> </em><em>slid</em><em> </em><em>down</em><em> </em><em>a</em><em> </em><em>slope</em><em>.</em>
  • <em>The</em><em> </em><em>arrow</em><em> </em><em>A</em><em> </em><em>is</em><em> </em><em>representing</em><em> </em><em>the</em><em> </em><em>force</em><em> </em><em>that</em><em> </em><em>is</em><em> </em><em>being</em><em> </em><em>applied</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>earth</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>block</em><em> </em><em>and</em><em> </em><em>that</em><em> </em><em>force</em><em> </em><em>is</em><em> </em><em>Gravitational</em><em> </em><em>Force</em><em>.</em><em> </em>
  • <em>So</em><em>,</em><em> </em><em>Option</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>correct</em><em> </em><em>choice</em><em>!</em><em>!</em><em>~</em>
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The drum of a washing machine spins at 200 rpm the drum had a radius of 0.5m what will the centripetal force experienced by a to
miskamm [114]

The centripetal force experienced by the towel is 55 N.

The given parameters;

  • angular speed of the washing machine, ω = 200 rpm
  • radius of the machine' drum, r = 0.5 m
  • mass of the towel, m = 0.25 kg

The centripetal force experienced by the towel spinning along the walls of the drum is calculated as follows;

Fc = mrω²

where;

<em>Fc is the centripetal force</em>

<em>ω is angular speed in rad/s</em>

The angular speed in rad/s is calculate as;

\omega = \frac{200 \ rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 \ s} \\\\\omega = 20.95 \ rad/s

The centripetal force experienced by the towel is calculated as;

F_c = mr\omega ^2\\\\F_c = 0.25 \times 0.5 \times (20.95)^2\\\\F_c = 54.9 \ N \ \approx 55 \ N

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3 years ago
The current theory of the structure of the
IRISSAK [1]

1) The mass of the continent is 3.3\cdot 10^{21} kg

2) The kinetic energy of the continent is 624 J

3) The speed of the jogger must be 4 m/s

Explanation:

1)

We start by finding the volume of the continent. We have:

L = 5850 km = 5.85\cdot 10^6 m is the side

t = 35 km = 3.5\cdot 10^4 m is the depth

So the volume is

V=L^2 t = (5.85\cdot 10^6)^2 (3.5\cdot 10^4)=1.20\cdot 10^{18} m^3

We also know that its density is

d=2750 kg/m^3

Therefore, we can find the mass by multiplying volume by density:

m=dV=(2750)(1.20\cdot 10^{18})=3.3\cdot 10^{21} kg

2)

The kinetic energy of the continent is given by:

K=\frac{1}{2}mv^2

where

m=3.3\cdot 10^{21} kg is its mass

v = 3.2 cm/year is the speed

We have to convert the speed into m/s. We have:

3.2 cm = 0.032 m

1 year = 1(365)(24)(60)(60)=3.15\cdot 10^7 s

So, the speed is:

v=\frac{0.032 m}{3.15 \cdot 10^7 s}=1.02\cdot 10^{-9} m/s

So, we can now find the kinetic energy:

K=\frac{1}{2}(1.20\cdot 10^{21})(1.02\cdot 10^{-9})^2=624 J

3)

Here we have a jogger of mass

m = 78 kg

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K = 624 J

The kinetic energy of the jogger is given by

K=\frac{1}{2}mv^2

where v is the speed of the jogger.

Solving for v, we find the speed that the jogger must have:

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Explanation:

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m = 49.9 kg

ρ = 270 kg/m³

<h2>Required:</h2>

volume

<h2>Equation:</h2>

ρ \:= \:\frac{m}{v}

where: ρ - density

m - mass

v - volume

<h2>Solution:</h2>

Substitute the value of ρ and m

ρ \:= \:\frac{m}{v}

270\: kg/m³\:= \:\frac{49.9\:kg}{v}

(v)\:270\: kg/m³\:= \:49.9\:kg

v\:= \:\frac{49.9\:kg}{270\: kg/m³}

v\:= \:0.1848\:m³

<h2>Final Answer:</h2><h3><u>Volume is 0.1848 m³</u></h3>
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High specific heat: Hydrogen bonds increase the amount of energy required for molecules to increase in speed, thereby raising the specific heat.

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High surface tension: Hydrogen bonds produce strong intermolecular  attractions, which increase surface tension

Explanation:

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